Regex non-greedy named capturing groups

Question

I need to parse the below text and read the value for id and name, and name is optional. I am getting 'txt" name="thistext' as the value for id.

input id="txt" name="thistext"

This is the regex I am using -

input\s+id="(?<id>.*)("+?)(?:(\s+name="(?<name>.*)(.*?")))?

Full match 0-30 input id="txt" name="thistext" Group id 10-29 txt" name="thistext Group 2. 29-30 "

can you add sample input and expected output? and also what you already got so far? — ACD, Dec 19 '18 at 01:47
you try this `input\s+id="(?.*?)(?:"+?)(?:(\s+name="(?.*?)(.*?")))?` https://regex101.com/r/KlTuJu/1/ — Code Maniac, Dec 19 '18 at 04:42

score 1 · Accepted Answer · answered Dec 19 '18 at 04:44

Your regex was almost correct except, you needed to do non-greedy capture in your id named group and change your regex to this,

input\s+id="(?<id>.*?)("+?)(?:(\s+name="(?<name>.*)(.*?")))?

Also, your regex is uselessly overly complex which you can simplify as this,

input\s+id="(?<id>[^"]*)"(?:\s+name="(?<name>[^"]*)")?

1 Answers1