TypeScript and React - children type?

Question

I have a very simple functional component as follows:

import * as React from 'react';

export interface AuxProps  { 
    children: React.ReactNode
 }


const aux = (props: AuxProps) => props.children;

export default aux;

And another component:

import * as React from "react";

export interface LayoutProps  { 
   children: React.ReactNode
}

const layout = (props: LayoutProps) => (
    <Aux>
        <div>Toolbar, SideDrawer, Backdrop</div>
        <main>
            {props.children}
        </main>
    <Aux/>
);

export default layout;

I keep on getting the following error:

[ts] JSX element type 'ReactNode' is not a constructor function for JSX elements. Type 'undefined' is not assignable to type 'ElementClass'. [2605]

How do I type this correctly?

Answer 1

Just children: React.ReactNode

Answer 2

In order to use <Aux> in your JSX, it needs to be a function that returns ReactElement<any> | null. That's the definition of a function component.

However, it's currently defined as a function that returns React.ReactNode, which is a much wider type. As React typings say:

type ReactNode = ReactChild | ReactFragment | ReactPortal | boolean | null | undefined;

Make sure the unwanted types are neutralized by wrapping the returned value into React Fragment (<></>):

const aux: React.FC<AuxProps> = props =>
  <>{props.children}</>;

Answer 3

This is what worked for me:

interface Props {
  children: JSX.Element[] | JSX.Element
}

Edit I would recommend using children: React.ReactNode instead now.

Answer 4

You can use ReactChildren and ReactChild:

import React, { ReactChildren, ReactChild } from 'react';
 
interface AuxProps {
  children: ReactChild | ReactChildren;
}

const Aux = ({ children }: AuxProps) => (<div>{children}</div>);

export default Aux;

If you need to pass flat arrays of elements:

interface AuxProps {
  children: ReactChild | ReactChild[] | ReactChildren | ReactChildren[];
}

Answer 5

You can also use React.PropsWithChildren<P>.

type ComponentWithChildProps = React.PropsWithChildren<{example?: string}>;

Answer 6

you can declare your component like this:

const MyComponent: React.FunctionComponent = (props) => {
    return props.children;
}

Answer 7

The function component return type is limited to JSXElement | null in TypeScript. This is a current type limitation, pure React allows more return types.

Minimal demonstration snippet

You can either use a type assertion or Fragments as workaround:

const Aux = (props: AuxProps) => <>props.children</>; 
const Aux2 = (props: AuxProps) => props.children as ReactElement; 

---

ReactNode

children: React.ReactNode might be suboptimal, if the goal is to have strong types for Aux.

Almost anything can be assigned to current ReactNode type, which is equivalent to {} | undefined | null. A safer type for your case could be:

interface AuxProps {
  children: ReactElement | ReactElement[]
}

Example:

Given Aux needs React elements as children, we accidently added a string to it. Then above solution would error in contrast to ReactNode - take a look at the linked playgrounds.

Typed children are also useful for non-JSX props, like a Render Prop callback.

Answer 8

A React Node is one of the following types:

• Boolean (which is ignored)
• null or undefined (which is ignored)
• Number
• String
• A React element (result of JSX)
• An array of any of the above, possibly a nested one

Answer 9

The general way to find any type is by example. The beauty of typescript is that you have access to all types, so long as you have the correct @types/ files.

To answer this myself I just thought of a component react uses that has the children prop. The first thing that came to mind? How about a <div />?

All you need to do is open vscode and create a new .tsx file in a react project with @types/react.

import React from 'react';

export default () => (
  <div children={'test'} />
);

Hovering over the children prop shows you the type. And what do you know -- Its type is ReactNode (no need for ReactNode[]).

Then if you click into the type definition it brings you straight to the definition of children coming from DOMAttributes interface.

// node_modules/@types/react/index.d.ts
interface DOMAttributes<T> {
  children?: ReactNode;
  ...
}

Note: This process should be used to find any unknown type! All of them are there just waiting for you to find them :)

Answer 10

From the TypeScript site: https://github.com/Microsoft/TypeScript/issues/6471

The recommended practice is to write the props type as {children?: any}

That worked for me. The child node can be many different things, so explicit typing can miss cases.

There's a longer discussion on the followup issue here: https://github.com/Microsoft/TypeScript/issues/13618, but the any approach still works.

Answer 11

These answers appear to be outdated - React now has a built in type PropsWithChildren<{}>. It is defined similarly to some of the correct answers on this page:

type PropsWithChildren<P> = P & { children?: ReactNode };

Answer 12

This has always worked for me:

type Props = {
  children: JSX.Element;
};

Answer 13

I'm using the following

type Props = { children: React.ReactNode };

const MyComponent: React.FC<Props> = ({children}) => {
  return (
    <div>
      { children }
    </div>
  );

export default MyComponent;

Answer 14

As a type that contains children, I'm using:

type ChildrenContainer = Pick<JSX.IntrinsicElements["div"], "children">

This children container type is generic enough to support all the different cases and also aligned with the ReactJS API.

So, for your example it would be something like:

const layout = ({ children }: ChildrenContainer) => (
    <Aux>
        <div>Toolbar, SideDrawer, Backdrop</div>
        <main>
            {children}
        </main>
    <Aux/>
)

Answer 15

React components should have a single wrapper node or return an array of nodes.

Your <Aux>...</Aux> component has two nodes div and main.

Try to wrap your children in a div in Aux component.

import * as React from 'react';

export interface AuxProps  { 
  children: React.ReactNode
}

const aux = (props: AuxProps) => (<div>{props.children}</div>);

export default aux;