why the second print result is None:
import re
pattern=r"(.+) \1" #notice that there is whitespace here before the backslash
match=re.match(pattern,"abc abc")
if match:
print(1) #1 was printed
match=re.match(pattern,"abc abd")
print(match) # None
Additionally,please give me another example for the usage of '\2'. Thx a lot.
Because in second example you have different values, abc and abd.
According to py mans, \number
Matches the contents of the group of the same number
https://docs.python.org/3.7/library/re.html
This means, it matches the contents of the group, not group's regular expression, so the second part is expected to be the same. This is the way to find other occurrences of the match.
Example for \2 is below:
(.+) (.+) \1 \2
will match
hello kitty hello kitty
