Why are the found matches of findall and finditer different?

Asked Oct 03 '18 at 15:37

Active Oct 03 '18 at 16:31

Viewed 21 times

I have made a regex with the findall and finditer methods, but they are different.
I need finditer to find matches like findall, and also need to know the span/indexes.

import re

string='This is my string.'

letters='abcdefghijklmnopqrstuvwxyzабвгґдеєжзиіїйклмнопрстуфхцчшщьюяыъэё'
letters+=letters.upper()+'\-\''

print(re.findall(rf'([{letters}]+?)(?:[^{letters}]|$)',string))
print(list(re.finditer(rf'([{letters}]+?)(?:[^{letters}]|$)',string)))

Output:
['This', 'is', 'my', 'string']
[<re.Match object; span=(0, 5), match='This '>, <re.Match object; span=(5, 8), match='is '>, <re.Match object; span=(8, 11), match='my '>, <re.Match object; span=(11, 17), match='string'>]

edited Oct 03 '18 at 16:31

asked Oct 03 '18 at 15:37

Igor Dragushhak

`[m.group(1) for m in re.finditer(rf'([{letters}]+?)[^{letters}]',string)]` or `[m.group() for m in re.finditer(rf'[{letters}]+?(?=[^{letters}])',string)]` – Steven Rumbalski Oct 03 '18 at 15:48
`findall` only returns the content of your capture groups. That is documented. If you're only interested in the captured text, you'll have to access the content of the first capture group with `finditer`. – Aran-Fey Oct 03 '18 at 15:50
And how I get the span of the group? – Igor Dragushhak Oct 03 '18 at 15:59
I need the indexes – Igor Dragushhak Oct 03 '18 at 16:05
The duplicate mentioned does not address `finditer`... this is not a duplicate. – Ctrl S Oct 03 '18 at 16:10
Is there an expression that says "find element but not include in the match"? – Igor Dragushhak Oct 03 '18 at 16:15
1

`indexes = [(m.start(), m.end()) for m in re.finditer(rf'[{letters}]+?(?=[^{letters}])',string)]` – Steven Rumbalski Oct 03 '18 at 16:27

Why are the found matches of findall and finditer different?

0 Answers0