Regex First Char of a String has to be uppercase, others lowercase

Asked Sep 09 '18 at 19:51

Active Sep 09 '18 at 19:52

Viewed 33 times

I need to write a method for username validation, and here are the restrictions:

So I need a regex to use to match string with regex. Please, help me out.

I just wrote this for now:

boolean matches= updatedName.matches( "(?<=\b[A-Z]+)[a-z]");

edited Sep 09 '18 at 19:52

41686d6564

asked Sep 09 '18 at 19:51

NigarMovsumova

1

Why are you using workarounds? You just need `^[A-Z][a-z]+$`. – 41686d6564 Sep 09 '18 at 19:53
2

`boolean matches = updatedName.matches("\\p{Lu}\\p{Ll}*")` – Wiktor Stribiżew Sep 09 '18 at 19:54
1

@WiktorStribiżew It's worth mentioning that this will match non-English letters, which might or might not be what the OP wants. – 41686d6564 Sep 09 '18 at 19:57
The first is for English, the second is for any language. The question did not restrict the language. – Jonathan Rosenne Sep 09 '18 at 19:58
Yeah, only English letters is fine. Thank you! Can I use this instead ? boolean matches= updatedName.matches( "[A-Z]([a-z]{2,10})?"); – NigarMovsumova Sep 09 '18 at 20:01
to use the length validation too, of course. For length to be between 3 and 11 – NigarMovsumova Sep 09 '18 at 20:03
@NigarMovsumova Why the `?` at the end though? Neither that nor the capturing group is required, otherwise, it will match a single uppercase letter. – 41686d6564 Sep 09 '18 at 20:05
Thanks to everyone! I used this version: boolean matches= updatedName.matches( "^[A-Z]([a-z]{2,10})$"); – NigarMovsumova Sep 09 '18 at 20:05

0 Answers0