Hello I'm a bit new at java and I need help.
Could someone explain to me how to make a request like this:
curl --data @FILE.xml -H 'content-type: application/xml' 'Host: URL' --cert ./FILE.crt:FILEPASS --key ./FILE.pem URL-REQUEST
(this already working at linux terminal) using java code. This sentence sends a XML file.
Thank you and have a nice day.
You could use a library like Apache HttpClient:
String url = "https://foourl.com";
TrustStrategy acceptingTrustStrategy = (cert, authType) -> true;
SSLSocketFactory sf = new SSLSocketFactory(
acceptingTrustStrategy, SSLSocketFactory.ALLOW_ALL_HOSTNAME_VERIFIER);
SchemeRegistry registry = new SchemeRegistry();
registry.register(new Scheme("https", 8443, sf));
ClientConnectionManager ccm = new PoolingClientConnectionManager(registry);
HttpClient client = new DefaultHttpClient(ccm);
HttpPost post = new HttpPost(url);
// set header
post.setHeader("User-Agent", "my-user-agent");
post.setHeader("Content-Type", "application/xml");
String xmlString = getXmlAsString();
List<NameValuePair> urlParameters = new ArrayList<NameValuePair>();
urlParameters.add(new BasicNameValuePair("xml", xmlString));
post.setEntity(new UrlEncodedFormEntity(urlParameters));
HttpResponse response = client.execute(post);
System.out.println("Response Code : " +
response.getStatusLine().getStatusCode());
BufferedReader rd = new BufferedReader(
new InputStreamReader(response.getEntity().getContent()));
StringBuffer result = new StringBuffer();
String line = "";
while ((line = rd.readLine()) != null) {
result.append(line);
}
System.out.println(result.toString());
Check these links: https://www.baeldung.com/httpclient-post-http-request https://www.baeldung.com/httpclient-ssl
Bear in mind that you need to parse the xml file as a string. Check this link: https://www.journaldev.com/1237/java-convert-string-to-xml-document-and-xml-document-to-string