how will be the regular expression in php for url pattern which doesn't start with "/ap1/v1"

Question

I am trying regular expression in php for url pattern matches url which doesnt start with "/api/v1".

^(?!/api/v1.*$).*

isn't working for me.

I am trying to configure it in symfony security config to match url patter for symfony security firewall

main:
    pattern: '^(?!/api/v1.*$).*'

Can you provide sample strings? That seems to work in the cases I've tried https://regex101.com/r/tIqREE/1/ — user3783243, Aug 04 '18 at 18:37
Probably, you used it wrong, try `if (preg_match('~^(?!/api/v1).*~', $url)) {return true;}` — Wiktor Stribiżew, Aug 04 '18 at 18:42
I am trying to configure it in symfony security config to match firewall url pattern, I mentioned it as it is mentioned in question. Updated question — vishal, Aug 04 '18 at 18:45
Patterns aren't enclosed between quote in yaml config files. Try to remove the quotes. Also, you can remove the useless `.*$` in the lookahead. — Casimir et Hippolyte, Aug 04 '18 at 19:08

score -1 · Answer 1 · answered Aug 04 '18 at 19:05

When I ran your expression through regexr.com it said ERROR: Unescaped forward slash. This may cause issues if copying/pasting this expression into code.

Adding a backslash before each of your forward slashes removed the error. Give this a try ^(?!\/api\/v1.*$).*

how will be the regular expression in php for url pattern which doesn't start with "/ap1/v1"

1 Answers1