Replace each char after specific word with * using regex JAVA

Question

I want to replace each char after 'to' with * using regex in Java.

Input:

String str = "thisisstringtoreplace"

Expected output:

thisisstringto*******

I am using

Pattern.compile("(?<=password=).*$")

This pattern replace all char with 1 * , I want * of remaining sting size (7 in this case). The action I want to perform is part of framework so I just need a regex for this.

I will give you a clue [indexOf(String str)](https://docs.oracle.com/javase/6/docs/api/java/lang/String.html#indexOf(java.lang.String)) — Guy, Aug 01 '18 at 10:33
what about [`String[] split = str.split("to"); String result = split[0] + "to" + String.format("%0" + split[1].length() + "d", 0).replace("0", "*");`](https://ideone.com/oFGTvT) — YCF_L, Aug 01 '18 at 10:39
Please let know what pattern you tried, it will be easier to see where you are wrong and help you better. — Wiktor Stribiżew, Aug 01 '18 at 10:39
Actually the action I want to [erform is part of framework so I just need a regex for this — Vishal Tank, Aug 01 '18 at 10:41
"I need" is not an appropriate problem statement. Your task is clear. What have you done to solve it? — Wiktor Stribiżew, Aug 01 '18 at 10:53
this pattern replace all char with 1 * , I want * of remaining sting size (7 in this case) — Vishal Tank, Aug 01 '18 at 10:56

score 0 · Accepted Answer · answered Aug 01 '18 at 11:40

0

You may use

s = s.replaceAll("(?<=\\G(?!^)|to).", "*");

See the regex demo.

Details

(?<=\G(?!^)|to) - either the end of the previous successful match or to
. - any char but a line break char.

answered Aug 01 '18 at 11:40

Wiktor Stribiżew

484,719
26
302
397

Replace each char after specific word with * using regex JAVA

1 Answers1