I have a text file with 300 lines. I am looking for a word "ABC" in each line If this word is found i want to print the line before it was found and then the next X lines. This is the code i have so far but i don't know how to print based on given problem statement.
path = ('C:\\Users\\40081\\PycharmProjects\\datalog_parsing')
count2=1
count1=1
num_lines = open('BBCnt123.txt').read().count('\n')
print (num_lines)
count2=count1
while count2<=num_lines:
file_name = open("BBCnt123.txt", 'r+')
f= open('BBCnt1234' + '.txt', 'w+')
for line_no, line in enumerate (file_name):
line=f.readlines()
if "BBCnt" in line:
f.writelines((line[count2-1]) )
count2= count2+1
file_name.close()
f.close()