1

Code -

echo "<li>";
echo "<img src='$image'/>";
echo "</li>";

$image contains the location of the image on the server. the above code is not working...no image is displayed.

thanks.

GOT IT WORKING GUYS..SORRY...THERE WAS AN ISSUE WITH $IMAGE...NYWAYS THANKS, AND GREAT COMMUNITY...PROUD TO BE A PART OF THE GROWING.

sarthaksss
  • 127
  • 6

0 Answers0