const result = 2
function dothis() {
const number = 5
if (number < 0) {
result == 0 ? console.log('error')
return false
}
}
Why is this code giving an "unexpected return" error?
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David Waters
- 15
- 3
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https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/Conditional_Operator – Hyyan Abo Fakher Jul 10 '18 at 13:44
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1`condition ? expr1 : expr2 ` – Alex Jul 10 '18 at 13:44
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where is result defined here and where is the else statement ? – Akhil Aravind Jul 10 '18 at 13:45
3 Answers
1
When using ternary condition you need to use the syntax condition?statement:statement. Thus, you are missing the third part, the statement, hence the name implies ternary(three parts).
var results = [];
function dothis() {
const number = -1;
if (number < 0) {
results.length == 0 ? console.log('error'): console.log('no error');
return false
}
}
dothis();
Ankit Agarwal
- 28,439
- 5
- 29
- 55
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So, I can't use a ternary without an 'else' statement? That was what I was going for. – David Waters Jul 10 '18 at 13:51
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@DavidWaters Looks like your after an if statement, `if (!results.length) console.log('error')` – Keith Jul 10 '18 at 13:54
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I was trying to do: if (results.length) { console.log('error') } return false – David Waters Jul 10 '18 at 13:54
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I thought I could use the ternary '?' in the same way as 'if' and not have to have the ': else' part – David Waters Jul 10 '18 at 13:56
1
I found out that your conditional if else shorthand is not completed, Else part is missing there.
function dothis() {
const number = 5
if (number > 0) {
results.length == 0 ? console.log('error') : console.log ('success')
return false
}
}this will complete your condition. Please let me know if you are trying to do something else.
Shashank Malviya
- 366
- 2
- 11
0
You're missing :
results.length == 0 ? console.log('error') : console.log('success')
Jorgedl
- 127
- 3