php regex ignoring "S" character

Asked Jul 09 '18 at 11:26

Active Jul 09 '18 at 11:26

Viewed 19 times

I'm trying to use the php regex command. My string is

localhost/uploads/125b77ed75d78dcba94f7527c9691c7b6cc20793/

Both the lines below return "1":

$dest = "localhost/uploads/125b77ed75d78dcba94f7527c9691c7b6cc20793/";
$res =  preg_match ( '/^localhost\/uploads\/*./' , $dest);

and

$dest = "localhost/uploads/125b77ed75d78dcba94f7527c9691c7b6cc20793/";
$res =  preg_match ( '/^localhost\/upload\/*./' , $dest);

The regex command seems to be ignoring the "s" character entirely. Am I missing something here?

Thanks in advance

asked Jul 09 '18 at 11:26

pedrumj

2

`*.` is not the same as `.*`. `\/*` matches 0+ `/`, so you do not require a `/` after `upload`, it may go missing, and `.` matches 1 char other than line break chars. – Wiktor Stribiżew Jul 09 '18 at 11:28
@WiktorStribiżew Right right, thank you! – pedrumj Jul 09 '18 at 11:30
are you trying to match the string after "uploads/" if so `(?<=(^localhost[\/]uploads[\/]))(.*)(?=[\/])` would work – Tom Jul 09 '18 at 11:32
@TomPowis OP just swapped the `.` and `*`, it is a typo question. – Wiktor Stribiżew Jul 09 '18 at 11:32

0 Answers0