regexp ignore some context after matching

Question

i want to solve regular expression in javascript for:

ignore } character wrapped context by quote. but must match } character out of quote.

example: "The sentense { he said 'hello, {somebody}', she said 'hi, {somebody}' } got a something."

result: { he said 'hello, {somebody}', she said 'hi, {somebody}' }

thanks for your help

Answer 1

The context is a little vague, but assuming you want the result to contain everything inside of (and including) the outer curly braces, you can just use /{.*}/g.

This can be seen in the following:

var regex = /{.*}/g;
var string = 'The sentense { he said "hello, {somebody}" } got a something.';

console.log(string.match(regex)[0]);

Or if you want to grab all three components, you can use the slightly-more-complicated regex
/({.*(?={))(.*(?<=.*}))(?:.*)}(.*)/g:

Breaking this down:

1. ({.*(?={)) - Group anything up to the second {
2. (.*(?<=.*})) - Grab everything inside the inner curly braces and group it
3. (?:.*) - Group anything up to the next }
4. } - Continue searching for the next } (but don't group it)
5. (.*) - Group anything after that

This can be seen in JavaScript here:

var regex = /({.*(?={))(.*(?<=.*}))(?:.*)}(.*)/g;
var string = 'The sentense { he said "hello, {somebody}" } got a something.';

string.replace(regex, function(match, g1, g2, g3) {
  console.log(match);
  console.log(g1);
  console.log(g2);
  console.log(g3);
});

And can be seen working on Regex101 here.