What should function signature look like to pass in 2D arrays of arbitrary size?

Question

I have a function that I want to accept 2D arrays of arbitrary size.

So if I have the following:

char names[100][10];
char values[100][5];

What should my function signature look like?

I tried:

void myFunc(char* names[], char* values[]); and void myFunc(char** names, char** values);

But then I get argument of type "char(*)[10]" is incompatible with parameter of type "char**".

I tried:

void myFunc(char names[][], char values[][]);

But then I get an array may not have elements of this type.

The only thing that works is void myFunc(char names[100][10], char values[100][5]);

But then it's not arbitrary size. I'm aware that I'll need to pass a size parameter as well, but I can't even get to that yet.

Life would be easier if you were permitted to use the standard library. — drescherjm, Jun 13 '18 at 17:56
I hate to flag duplicates when the duplicate has so many terrible, terrible answers... — François Andrieux, Jun 13 '18 at 17:56
Long ago I decided that the answer to this question is "You don't." Use a C++ structure of some kind to map 2D (or more) indexes onto a single 1D array allocation. Or possibly multiple 1D arrays. — Zan Lynx, Jun 13 '18 at 17:56
I'd rather do `struct myPair { char name[10];char value[5]; }; myPair pairs[100]`; probably you are actually looking for `std::map` — Stephan Lechner, Jun 13 '18 at 18:00
@ZanLynx I'm starting to think you're right. MD arrays in C++ are a trash fire. — Legion, Jun 13 '18 at 18:05

0 Answers0