How to click the "logout" link as per the html through selenium and java

Question

Here is the code,

<div id="user-tools">
    Welcome
    <strong>Admin</strong>
    /
    <a href="/">View</a>
    /
    <a href="/admin/password_change>Change password</a>
    /
    </a href="/admin/logout/">Log out</a>
</div>

And I am trying to use this way to click the "Log out" link, but no luck.

driver.findElement(By.xpath("//a[@href='/admin/logout/'])".click();

Any ideas ? Thanks.

Try using `driver.findElement(By.linkText("Log out")).click();` — Mangohero1, Jun 08 '18 at 18:59
What do you mean by *"failed"*? Why opening anchor tag is actually closing tag? — Andersson, Jun 08 '18 at 19:19
It looks like your statement is mal-formed. You are missing an ending parenthesis and the double quotes wraping the XPath need to be inside the first ending parens: `driver.findElement(By.xpath("//a[@href='/admin/logout/']")).click();` — Mads Hansen, Jun 08 '18 at 19:22

DebanjanB · Accepted Answer · 2018-06-08T19:32:01.197

1

To click on the element with text as Log out you can use either of the following Locator Strategies:

CssSelector:

"div#user-tools a[href='/admin/logout/']"

XPath:

"//div[@id='user-tools']//a[@href='/admin/logout/'][contains(.,'Log out')]"

edited Jun 08 '18 at 19:32

answered Jun 08 '18 at 19:22

DebanjanB

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How to click the "logout" link as per the html through selenium and java

1 Answers1