Scanner is not taking input of another string and skipping it

Question

Why scanner is not taking input of another string and skepping it? I cant understand, here is my code:

import java.util.Scanner;

public class demo {

    public static void main(String[] args) {

        Scanner s = new Scanner(System.in);
        String name;
        String address;
        int age;

        System.out.println("Enter your name");
        name = s.nextLine();
        System.out.println("My name is :" + name);

        System.out.println("Enter your age");
        age = s.nextInt();
        System.out.println("My age is :" + age);

        System.out.println("Enter your address");
        address = s.nextLine();
        System.out.println("My address is :" + address);
    }
}

Output :

Enter your name
dk
My name is :dk
Enter your age
22
My age is :22
Enter your address
My address is :

Possible duplicate of [Scanner is skipping nextLine() after using next() or nextFoo()?](https://stackoverflow.com/questions/13102045/scanner-is-skipping-nextline-after-using-next-or-nextfoo) — Roshana Pitigala, Jun 04 '18 at 09:33

score 1 · Answer 1 · edited Jun 04 '18 at 09:32

1

It is simple. You can use s.nextLine(); after the age = s.nextInt();

Scanner provides a method nextInt() to request user input and does not consume the last newline character (\n).

System.out.println("Enter your age");
age = s.nextInt();
s.nextLine(); // consumes the \n character
System.out.println("My age is :" + age);

edited Jun 04 '18 at 09:32

Roshana Pitigala

7,058
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answered Jun 04 '18 at 08:19

Poorna Senani Gamage

1,170
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score 0 · Answer 2 · answered Jun 04 '18 at 07:56

0

You should close the scanner after the last system out

answered Jun 04 '18 at 07:56

Maria Fatu

1
1

(This post does not seem to provide a [quality answer](https://stackoverflow.com/help/how-to-answer) to the question. Please either edit your answer, or just post it as a comment to the question). – sɐunıɔןɐqɐp Jun 04 '18 at 08:08
This does not help to solve the issue. Add example code. – Roshana Pitigala Jun 04 '18 at 09:23

score 0 · Answer 3 · edited Jun 04 '18 at 11:14

0

Place below statement after Statement.out.println("My age is",age);

s.nextLine();

Above statement will do flush, which will clear the cache location in order to accept new input.

edited Jun 04 '18 at 11:14

an33sh

934
16
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answered Jun 04 '18 at 09:51

user9891512

1

Scanner is not taking input of another string and skipping it

3 Answers3

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