Why for loop is printing sop first and then running rest of code (see code inside)

Asked Apr 23 '18 at 06:34

Active Apr 23 '18 at 06:42

Viewed 41 times

Which I run in eclipse. I am getting an unusual output (see below)

import java.util.Scanner;

public class Sample {

    public static void main(String[] args) {
        int testcase ;
        String s1;
        String s2;
        Scanner sc = new Scanner(System.in);
        System.out.println("Enter test cases");
        testcase = sc.nextInt();

for(int i=1 ; i<=testcase; i++)
{
    System.out.println("Enter String 1");
    s1= sc.nextLine();
    System.out.println("Enter String 2");
    s2= sc.nextLine();
    System.out.println(WeightChecker.checkStringWeight(s1, s2));
}


}

the output is

Enter test cases
2
Enter String 1
Enter String 2
timepass
2
Enter String 1
time
Enter String 2
starts
2

I even used debug and here in first iteration s1="" and s2="" my question is why it is happening here?

and what could be the possible solution for same

I saw people is marking this question to another question but that question is completely different

edited Apr 23 '18 at 06:42

asked Apr 23 '18 at 06:34

timepass

Maybe something stays in the stamp when you enter `2` before the loop.. aaaand.. yup, `\n` it is, right? – Rafalon Apr 23 '18 at 06:37
http://stackoverflow.com/questions/13102045/scanner-is-skipping-nextline-after-using-next-nextint-or-other-nextfoo – Scary Wombat Apr 23 '18 at 06:37
Maybe try using sc.next(); , before – EOxJ Apr 23 '18 at 08:45
Maybe try using ###sc.next(); before the ###for-loop right after the ###testcase = sc.nextInt(); – EOxJ Apr 23 '18 at 08:48

Why for loop is printing sop first and then running rest of code (see code inside)

0 Answers0