How to instantiate a generic array?

Asked Apr 10 '18 at 21:46

Active Apr 10 '18 at 21:46

Viewed 31 times

I've some issues trying to instantiate an array of templated type :

public class MyList<T extends Comparable<T>> {

  private T[] data;

  /**
   * Initializes the list
  **/
  public MyList() {
    data = new T[0];
  }

  // ...
}

I assume that the type of T is defined during runtime, isn't it ?

Regards,

asked Apr 10 '18 at 21:46

Pyrrha

No... it's not. – shmosel Apr 10 '18 at 21:48
No T is erased at runtime. You need to read the java tutorial on generics and erasure to understand why you can’t write new T[0] – cpp beginner Apr 10 '18 at 21:48
1

As other's have hinted, the type which T actually stands for is determined at compile time. – Code-Apprentice Apr 10 '18 at 21:51

How to instantiate a generic array?

0 Answers0