I have written this code but I have a little problem with it. This code should get a string and check whether this string contains all the alphabet letters... If it doesnt the output is "Not a pangramma!". If it does "PanGramma!". The probem is that I want it to count also the nuumber of the spaces between the words. But when the input is string with at least one space the output will always be "Not a PanGramma!", even if it contains all the alphabet letters. Can someone please help me?
#include <stdio.h>
char UpCase (char c);
int isPangram (char *str);
int main()
{
char str[100];
printf("Please enter yout string: \n");
scanf("%s", str);
if (isPangram (str) == 1)
{
printf("PanGramma!\n");
}
else
{
printf("Not a PanGramma!\n");
}
return 0;
}
char UpCase (char c)
{
if (c>='a' && c<='z')
{
return c-'a'+'A';
}
return c;
}
int isPangram (char *str)
{
int i=0;
int hist[27]={0};
while (str[i] !=0)
{
str[i]=UpCase(str[i]);
if (str[i] == ' ')
{
hist[26]++;
}
else
{
hist[str[i] - 'A']++;
}
i++;
}
for (i=0; i<26; i++)
{
if(hist[i] == 0)
{
return 0;
}
}
return 1;
}