How to get a variable from the .getJSON function

Asked Feb 08 '18 at 13:15

Active Feb 08 '18 at 13:15

Viewed 19 times

I want to get the result of the .getJSON function to be accessible from outside the function. Here is my code:

var saveResult;
    $.getJSON($query, function(result){
        console.log("Result " +result);
        saveResult = result
        console.log(saveResult)
    });

telemetry = saveResult;
console.log(telemetry);

Inside the function, the variable saveResult is printed at the right way in the console. But outside the function, it is printed as undefined.

How can I get the right data outside of the function aswell?

Thanks in advance!

asked Feb 08 '18 at 13:15

disprog

What exactly do you want to achieve with this? – void Feb 08 '18 at 13:17
The problem might be that the getJSON is async. So, by the time it executes, the log is already printed. – Faizuddin Mohammed Feb 08 '18 at 13:17
`$.getJSON` is async. – Eddie Feb 08 '18 at 13:17
@Eddie is there an easy way to solve this? – disprog Feb 08 '18 at 13:22
Basically, when you do `console.log(telemetry);` outside you are printing the `telemetry` before you even receive the data from the backend. That is why you are getting undefined. – Eddie Feb 08 '18 at 13:24
You have to wait for `success` function before you can print the value. – Eddie Feb 08 '18 at 13:25
@Eddie and when does it give success? – disprog Feb 08 '18 at 13:34
On your callback function. where are you are able to `console.log(saveResult)` successfully. – Eddie Feb 08 '18 at 13:40
This where you can process or call a different function to handle the `saveResult` variable. – Eddie Feb 08 '18 at 13:40
Okay thanks, can you please post an answer/solution to this question? Thanks! – disprog Feb 08 '18 at 13:43
I cant. This post is marked as duplicate. Nobody can answer to this post. You have to base the answers on https://stackoverflow.com/questions/14220321/how-do-i-return-the-response-from-an-asynchronous-call – Eddie Feb 08 '18 at 13:49

How to get a variable from the .getJSON function

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