47

How can I check if I'm connected to the internet from my PHP script which is running on my dev machine?

I run the script to download a set of files (which may or may not exist) using wget. If I try the download without being connected, wget proceeds to the next one thinking the file is not present.

Steve
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11 Answers11

87
<?php
function is_connected()
{
    $connected = @fsockopen("www.example.com", 80); 
                                        //website, port  (try 80 or 443)
    if ($connected){
        $is_conn = true; //action when connected
        fclose($connected);
    }else{
        $is_conn = false; //action in connection failure
    }
    return $is_conn;

}
?>
Thamaraiselvam
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Alfred
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    + Nice answer be someone else might think `[80|443]` would switch between any of the ports ... :) – Baba Apr 04 '13 at 21:23
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    Based on [this](https://www.quora.com/Downtime/What-is-the-most-reliable-website-in-terms-of-uptime) post, it would probably make a lot of sense to use example.com as the "www.some_domain.com" of the answer. – nzn Feb 02 '16 at 19:16
9

You can always ping good 'ol trusty google:

$response = null;
system("ping -c 1 google.com", $response);
if($response == 0)
{
    // this means you are connected
}
Gabi Purcaru
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    This is quite reliable, but keep in mind that "ICMP works != TCP works" (what with firewalls, NATs and whatnot), and even "TCP works != HTTP works" (transparent proxies etc.). – Piskvor left the building Feb 01 '11 at 09:26
8

This code was failing in laravel 4.2 php framework with an internal server 500 error:

<?php
     function is_connected()
     {
       $connected = @fsockopen("www.some_domain.com", 80); 
        //website, port  (try 80 or 443)
       if ($connected){
          $is_conn = true; //action when connected
          fclose($connected);
       }else{
         $is_conn = false; //action in connection failure
       }
      return $is_conn;
    }
?>

Which I didn't want to stress myself to figure that out, hence I tried this code and it worked for me:

function is_connected()
{
  $connected = fopen("http://www.google.com:80/","r");
  if($connected)
  {
     return true;
  } else {
   return false;
  }

} 

Please note that: This is based upon the assumption that the connection to google.com is less prone to failure.

user28864
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  • Nice alternative! This also requires `allow_url_fopen = On` in php.ini – zanderwar Aug 06 '19 at 05:27
  • In my tests fopen is twice slower than the fsockopen alternative. Also, it would look nicer this syntax instead of an ugly if() with return true/false: return (bool) fopen("http://www.google.com:80/","r"); – aFeijo Jan 15 '20 at 14:02
4

The accepted answer did not work for me. When the internet was disconnected it threw a php error. So I used it with a little modification which is below:

if(!$sock = @fsockopen('www.google.com', 80))
{
    echo 'Not Connected';
}
else
{
echo 'Connected';
}
hilbiazhar
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3

Why don't you fetch the return code from wget to determine whether or not the download was successful? The list of possible values can be found at wget exit status.

On the other hand, you could use php's curl functions as well, then you can do all error tracking from within PHP.

wimvds
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1

There are various factors that determine internet connection. The interface state, for example. But, regardles of those, due to the nature of the net, proper configuration does not meen you have a working connection.

So the best way is to try to download a file that you’re certain that exists. If you succeed, you may follow to next steps. If not, retry once and then fail.

Try to pick one at the destination host. If it’s not possible, choose some major website like google or yahoo.

Finally, just try checking the error code returned by wget. I bet those are different for 404-s and timeouts. You can use third parameter in exec call:

string exec ( string $command [, array &$output [, int &$return_var ]] )

Maciej Łebkowski
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1
/*
 * Usage: is_connected('www.google.com')
 */
function is_connected($addr)
  {
    if (!$socket = @fsockopen($addr, 80, $num, $error, 5)) {
      echo "OFF";
    } else {
      echo "ON";
    }
  }
cagcak
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1

Also note that fopen and fsockopen are different. fsockopen opens a socket depending on the protocol prefix. fopen opens a file or something else e.g file over HTTP, or a stream filter or something etc. Ultimately this affects the execution time.

0

This function handles what you need

function isConnected()
{
    // use 80 for http or 443 for https protocol
    $connected = @fsockopen("www.example.com", 80);
    if ($connected){
        fclose($connected);
        return true; 
    }
    return false;
}
Lost Koder
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0

You could ping to a popular site or to the site you're wgetting from (like www.google.nl) then parse the result to see if you can connect to it.

<?php
$ip = '127.0.0.1'; //some ip
exec("ping -n 4 $ip 2>&1", $output, $retval);
if ($retval != 0) { 
echo "no!"; 
} 
else 
{ 
echo "yes!"; }
?>
Roy T.
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0

Just check the result of wget. A status code of 4 indicates a network problem, a status code of 8 indicates a server error (such as a 404). This only works if you call wget for each file in sequence, rather than once for all the files.

You can also use libcurl with PHP, instead of calling wget. Something like:

foreach (...) {
    $c = curl_init($url);
    $f = fopen($filepath, "w")
    curl_setopt($c, CURLOPT_FILE, $f);
    curl_setopt($c, CURLOPT_HEADER, 0);
    if (curl_exec($c)) {
        if (curl_getinfo($c, CURLINFO_HTTP_CODE) == 200) {
            // success
        } else {
            // 404 or something, delete file
            unlink($filepath);
        }
    } else {
        // network error or server down
        break; // abort
    }
    curl_close($c);
}
Dietrich Epp
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