symfony 4 : How to get "/public" from RootDir

Question

I have an image under the public folder.
How can I get my image directory in symfony4 ?
In symfony 3, it's equivalent is :

$webPath = $this->get('kernel')->getRootDir() . '/../web/';

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Possible duplicate of [How do I read from parameters.yml in a controller in symfony2?](https://stackoverflow.com/questions/13901256/how-do-i-read-from-parameters-yml-in-a-controller-in-symfony2) — Tomas Votruba, Dec 21 '18 at 16:59

score 30 · Answer 1 · answered Aug 07 '19 at 11:56

It is a bad practice to inject the whole container, just to access parameters, if you are not in a controller. Just auto wire the ParameterBagInterface like this,

protected $parameterBag;

public function __construct(ParameterBagInterface $parameterBag)
{
    $this->parameterBag = $parameterBag;

}

and then access your parameter like this (in this case the project directory),

$this->parameterBag->get('kernel.project_dir');

Hope someone will find this helpful.

Cheers.

score 27 · Accepted Answer · answered Feb 02 '18 at 15:02

27

You can use either

$webPath = $this->get('kernel')->getProjectDir() . '/public/';

Or the parameter %kernel.project_dir%

$container->getParameter('kernel.project_dir') . '/public/';

answered Feb 02 '18 at 15:02

goto

7,020
10
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50

5

Worth to mention that the controller needs to extend the Symfony\Bundle\FrameworkBundle\Controller\Controller class, not the abstract one that you find on most examples Symfony\Bundle\FrameworkBundle\Controller\AbstractController – Carlos Delgado Aug 17 '18 at 18:30
7

worth to mention @CarlosDelgado that the controller class you mentioned is being deprecated in Symfony 4.2 `@deprecated since Symfony 4.2, use {@see AbstractController} instead.` – Dragos Dec 29 '18 at 17:04

score 8 · Answer 3 · answered Mar 21 '19 at 09:02

8

In Controller (also with inheriting AbstractController):

$projectDir = $this->getParameter('kernel.project_dir');

answered Mar 21 '19 at 09:02

godrar

91
1
2

Why did you downvote this? This is the only one that worked for me?! – Aries VII Aug 07 '19 at 12:01
@godrar because we're talking about Symfony 4 where your controllers should be defined as services thus, not inheriting from AbstractController. – DevAntoine Oct 01 '19 at 15:20
@vdavid Yes, it worked in old versions. In the new version you do not have access to the kernel in this way (inject "container" is bad practice) – godrar Oct 03 '19 at 10:58

score 5 · Answer 4 · answered Feb 01 '19 at 12:54

5

parameters:
    webDir: '%env(DOCUMENT_ROOT)%'

answered Feb 01 '19 at 12:54

Nexen

94
1
3

Moving forward to Symfony 4 and beyond, this is closer to the real answer. $this->get('kernel') is deprecated in 4.2. – tlorens Apr 10 '19 at 12:16

score 4 · Answer 5 · answered Jan 10 '20 at 19:24

You can inject KernelInterface to the service or whatever and then get the project directory with $kernel->getProjectDir():

<?php

namespace App\Service;

use Symfony\Component\HttpKernel\KernelInterface;

class Foo
{
    protected $projectDir;

    public function __construct(KernelInterface $kernel)
    {
        $this->projectDir = $kernel->getProjectDir();
    }

    public function showProjectDir()
    {
        echo "This is the project directory: " . $this->projectDir;
    }
}

score 0 · Answer 6 · answered Apr 08 '21 at 16:08

Starting from Symfony 4.3 we can generate absolute (and relative) URLs for a given path by using the two methods getAbsoluteUrl() and getRelativePath() of the new Symfony\Component\HttpFoundation\UrlHelper class.

New in Symfony 4.3: URL Helper

public function someControllerAction(UrlHelper $urlHelper)
{
    // ...
    return [
        'avatar' => $urlHelper->getAbsoluteUrl($user->avatar()->path()),
        // ...
    ];
}

symfony 4 : How to get "/public" from RootDir

6 Answers6

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