after a integer input, I want to concatenate two strings, one already initialize and another one is user input

Question

int i = 4;
String s ="Hi ";

Scanner scan = new Scanner(System.in);

System.out.println("enter Integer");
int m=scan.nextInt();

System.out.println("enter string");
*String t = scan.next();
**String t = scan.nextLine();

System.out.println(i+m);
System.out.println(s+t);

when I use *scan.next() then it will only read a single word, another side when I use **scan.nextLine() it will directly show the output

Possible duplicate of [Scanner is skipping nextLine() after using next(), nextInt() or other nextFoo()?](https://stackoverflow.com/questions/13102045/scanner-is-skipping-nextline-after-using-next-nextint-or-other-nextfoo) — OH GOD SPIDERS, Dec 05 '17 at 12:16
`nextInt` let the `` in the buffer, so the next `nextLine` read that. Check the duplicate above for a complete answer. — AxelH, Dec 05 '17 at 12:17
Can you add this line: scan.nextLine(); after your int m = scan.nextInt(); just do that and let me know if it works. — whatamidoingwithmylife, Dec 05 '17 at 12:18

The Mighty Programmer · Answer 1 · 2017-12-05T12:32:31.670

Call nextLine() after nextint() to consume \n.

int a = scanner.nextInt()
scanner.nextLine() // to flush end of line
 ... // Then read string
String s = scanner.next()

The whole story

After Entering a number, Say 5.. the stream looks like

5\n

When nextInt() is called, the stream looks like

\n

After you enter string, say `hi

\nhi

After next() is called the stream looks like

hi

The cause of problem: next() consume till \n.
When it is called \n was first character in the stream. so it read empty string "".

after a integer input, I want to concatenate two strings, one already initialize and another one is user input

1 Answers1