Break line not executing

Question

while True:
password = input('Enter your password')
passwordlist = list(password)
upper=False
lower=False
for letters in passwordlist:
    if letters == letters.upper():
        upper = True
    if letters == letters.lower():
        lower = True
    if len(password) <=5:
        print('password is to short')
    elif Name in password or Surname in password:
        print('You cannot have first or last name in password')
    elif upper == False or lower == False:
        print('You must have both upper and lower case in password')
    elif upper == True and lower == True:
        print('Password is valid')
    break

When I run my code it is able to see if I use my first and last name, but it is not able to determine if I have used both upper and lower case as if my password contains both it returns me with You must have both upper and lower case in password even though I have used both

So my question is why my code is not able to detect both upper and lower case letters in password. Why does my break line not execute

your break line executes at first iteration, unless you have a formatting problem in your question. — Jean-François Fabre, Dec 01 '17 at 20:30
`upper == True and lower == True` cannot happen. You should check `isupper` & `islower` function. — Jean-François Fabre, Dec 01 '17 at 20:30
You definitely have formatting issues in the code you posted. Please check the indentation and correct any mistakes. — Bill the Lizard, Dec 01 '17 at 20:34
Since your question was marked as duplicated I answered it in here: https://stackoverflow.com/questions/39991064/in-python-how-do-you-check-if-a-string-has-both-uppercase-and-lowercase-letters/47601526#47601526 Check the isupper and islower that @Jean-François Fabre wrote about. — epinal, Dec 01 '17 at 21:09

Break line not executing

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