Python ternary operator check most left reference

Asked Oct 31 '17 at 17:09

Active Oct 31 '17 at 17:09

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What is the pythonic way to write a ternary operator like this in the shortest possible way?

(x!=null)? x.something:0;

I want to use something like

y = x.something or 0

but that will check references in a way such that

x.y.z = None whenever x or y are None

asked Oct 31 '17 at 17:09

monolith

Thank you for your suggestion, that's what i've been looking for ! – monolith Oct 31 '17 at 17:13
So, do you want a ternary conditional operator, or something like the [null-conditional operator that exists in C#](https://docs.microsoft.com/en-us/dotnet/csharp/language-reference/operators/null-conditional-operators)? – Blorgbeard Oct 31 '17 at 17:13
Found it in the marked answer. Basically: a if condition else b would be something like x.something if x else 0. Thanks anyway :) – monolith Oct 31 '17 at 17:15
Ok, that won't work for `x.y.z` as in your last example, though. – Blorgbeard Oct 31 '17 at 17:16
x.y.z if (x.y if x else None) else 0 – monolith Oct 31 '17 at 17:27
1

Yup, but that approach doesn't exactly scale easily - `a.b.c.d.e.f` would look ugly :P – Blorgbeard Oct 31 '17 at 17:29

0 Answers0