How to define Long Long data type in kotlin?

Question

fun main(args: Array<String>) {
    try {
        var sum: Long = 0
        val n: Int = readLine()!!.toInt()

        for (i in 0..(n - 1)) {
            var input: Long?
            input = readLine()!!.toLong()
            sum += input
        }
        println(sum)
    } catch (ex: Exception) {
        println(ex.message)
    } 
}

I want to take data Type Long Long replacing at Long . So how can I define Long Long data type?

As evident by the fundamentally differing answers, you should edit your question to include some context. What would this supposed `Long Long` do for you that `Long` doesn't? — chris, Oct 23 '17 at 18:57
Java itself has no `long long` type. `long` is 64-bit, `int` is 32-bit, `short` is 16-bit and `byte` is 8-bit. Kotlin doesn't change this. — Moira, Oct 23 '17 at 19:57

score 9 · Answer 1 · answered Oct 23 '17 at 18:33

9

Kotlin's Long is 64-bit already. No need for ancient long long trickery:

https://kotlinlang.org/docs/reference/basic-types.html

answered Oct 23 '17 at 18:33

Marcin Orlowski

67,279
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score 2 · Answer 2 · answered Oct 23 '17 at 18:34

2

If you're on the JVM, there isn't a long long type, but you could use java.math.BigInteger for arbitrarily large numbers instead.

See more discussion on this topic and some more alternatives at a Java question here.

answered Oct 23 '17 at 18:34

zsmb13

69,803
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score 0 · Answer 3 · answered Sep 27 '20 at 22:03

Kotlin handles long long data type with the BigInteger data type. Replace the long with BigInteger;

fun main(args: Array<String>) {
    try {
        var sum = 0.toBigInteger()
        val n: Int = readLine()!!.toInt()

        for (i in 0..(n - 1)) {
            var input: BigInteger?
            input = readLine()!!.toBigInteger()
            sum += input
        }
        println(sum)
    } catch (ex: Exception) {
        println(ex.message)
    } 
}

How to define Long Long data type in kotlin?

3 Answers3