How to do regexp replace/search

Question

I am following some instructions for data upload. I can't figure out what the following two points mean. Does anyone have any idea?

Regexp search/replace
- search: 201([0-9])([0-9])([0-9])([0-9][0-9]) ([0-9])
- replace:201\1\2\3\4 \5
Regexp search/replace
- replace 20110401 with whatever year month day that is being fixed ^(.{462}) \120110401

I have tried to fix the formatting of your question, but I think the last part is wrong. Please [edit] it and fix any mistakes I might have made. Also, please add a tag for whatever language or tool you are trying to use to solve the problem. — Chris, Aug 09 '17 at 17:12

score 0 · Accepted Answer · answered Aug 09 '17 at 16:16

Any decent regex tutorial will help.

() wrap groups that can be referenced later with \#. For example, \2 references the token matched by the second pair of parentheses.

[0-9] means any character between 0-9 inclusive.

^ is the left anchor (i.e., start of string or new line), and .{462} means any character, 462 times.

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