I was wondering why the example will return 'global' not 'obj2'? And what's different between '(obj2.say = obj1.say)()' and '(obj2.say)()'? Here is the code:
var text = 'global';
var obj1 = { text: 'obj1', say: function () {console.log(this.text)}};
var obj2 = { text: 'obj2'};
(obj2.say = obj1.say)();
The result of an assignment is the value that was assigned. Example:
var foo, bar;
foo = (bar = 42);
console.log(foo); // 42
Hence when you do (obj2.say = obj1.say), the result of the assignment, was returned by the grouping operator, is the function object in obj1.say.
The whole expression to be be equivalent to
var result = obj2.say = obj1.say;
result();
And when a function is called the "normal" way (func()), this refers to the global object or is undefined in strict mode.
(obj2.say)() is quite special actually. The grouping operator alone does not resolve (internal) references to values. I.e. the result of obj2.say is, internally, a reference that describes the member access say on obj2. The grouping operator, (...) returns that reference unchanged, not resolving it to the actual function object. That's why this will correctly point to obj2. Omitting the grouping operator has the same effect.
This is actually called out in the spec:
This algorithm does not apply
GetValueto the result of evaluating Expression. The principal motivation for this is so that operators such asdeleteandtypeofmay be applied to parenthesized expressions.
Because the value of (obj2.say = obj1.say) is a plain Function object, while obj2.say() is a method call with obj2.
(obj2.say)() will just call the say function from obj2.
(obj2.say = obj1.say)() will assign obj1.say to obj2.say and then call it.
I am not sure about the this.text - I'm hoping someone can help with that - even I am curious to find that out.
