For example if:
String str = "100101010";
Then following should happen:
a[0]=1
a[1]=0
a[2]=0
...
It should hold for large strings also (up to 64 characters).
For example if:
String str = "100101010";
Then following should happen:
a[0]=1
a[1]=0
a[2]=0
...
It should hold for large strings also (up to 64 characters).
One hint: find a chart for ASCII. http://www.asciitable.com/index/asciifull.gif The code for "0" is 48 and the code for "1" is 49. You can convert characters to numbers just by subtracting 48 from the ASCII value.
int value = str.charAt(0) - 48;
It's important to realize that a Java char
is just an integer type just like int
and byte
. You can do math with them. With that idea in mind, you should be able figure out the rest yourself.
(This is technically a duplicate since I answered a similar question long ago, but I can't find it, so you get a freebie.)
public static int[] getAsArray(String value){
// not null ; not empty ; contains only 0 and 1
if(value == null || value.trim().length()<1 || !value.matches("[0-1]+")){
return new int[0];
}
//if it necessary !value.matches("[0-1]+" regex to validate
value = value.trim();
value = value.length()>64 ? value.substring(0,63) : value;// up to 64 characters
int[] valueAsInt = new int[value.trim().length()];
for (int i = 0 ;i<value.length();i++){
valueAsInt[i]=(int)value.toCharArray()[i]-48;
}
return valueAsInt;
}
also if it's possible use shor or byte type as it's enoght to store 0,1 and you consume less memory as with int
I don't know why you want to do this, but it is a simple problem.
public static void main (String[] args) {
String s = "111232";
String element[] = s.split("");
System.out.println(element[0]);
System.out.println(element[1]);
System.out.println(element[2]);
System.out.println(element[3]);
System.out.println(element[4]);
System.out.println(element[5]);
}