What is the equivalent in python of the expression below?
EE_DOUBLE const yplus = ( y < 1.0 ) ? y*u_tau/nu_inf : (2.0-y)*u_tau/nu_inf
Any suggestions are welcome. Many thanks A
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too honest for this site
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Andrei
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1What is the confusion? Do you know what ternary operator is? – Eugene Sh. Jun 22 '17 at 14:59
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1https://stackoverflow.com/questions/394809/does-python-have-a-ternary-conditional-operator – taras Jun 22 '17 at 15:00
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I am afraid that I don't know Eugene. – Andrei Jun 22 '17 at 15:00
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So you have an excellent opportunity to learn about it! You have the keyword, you know what to do. – Eugene Sh. Jun 22 '17 at 15:01
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@EugeneSh. didn't know the term either, nice link ! – Tbaki Jun 22 '17 at 15:04
3 Answers
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I'm not too sure about C syntax anymore, but i guess it'll look like this :
yplus = y*u_tau/nu_inf if ( y < 1.0 ) else (2.0-y)*u_tau/nu_inf
Tbaki
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yplus = ((2.0-y)*u_tau/nu_inf, y*u_tau/nu_inf)[y < 1.0]
other way
yplus = (y < 1.0) and (y*u_tau/nu_inf) or ((2.0-y)*u_tau/nu_inf)
other way
yplus = {True: y*u_tau/nu_inf, False: (2.0-y)*u_tau/nu_inf} [y < 1.0]
other way marked already by others
yplus = (y*u_tau)/nu_inf if y < 1.0 else (2.0-y)*u_tau/nu_inf
other way
if (y < 1.0):
yplus = (y*u_tau)/nu_inf
else:
yplus = (2.0-y)*u_tau/nu_inf
alinsoar
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I guess the expressions should be swapped. But nice idea. Is it idiomatic? – Eugene Sh. Jun 22 '17 at 15:17
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@EugeneSh. the idea comes from lisp systems, where each operator can treat a value in different ways, for example here what is supposed to be a boolean is treated by []-ref operator as integer. – alinsoar Jul 03 '17 at 06:01
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Using Python's ternary operator added since 2.5
yplus = (y*u_tau)/nu_inf if y < 1.0 else (2.0-y)*u_tau/nu_inf
Peter Krasinski
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