React Native Open settings through Linking.openURL in IOS

Question

I want to open ios setting app from my app. the settings destination is [ settings => notification => myapp ]. to turn on & turn off push notification.

There are some documents about how to link to settings, but I don't know how to open deep link. (notification => myapp).

How can I do this?

how to open external app after button click in my app – Avishkar Patil Nov 18 '19 at 12:28 — Avishkar Patil, Nov 18 '19 at 12:28

score 32 · Accepted Answer · answered Jun 16 '17 at 07:04

32

You can deep-link referencing the settings's index like so:

Linking.openURL('app-settings:')

Above method only for IOS

answered Jun 16 '17 at 07:04

Arunkumar

1,555
1
14
25

1

How to access deeper? to 'notification => myapp' . .that is my question... – JuntaeKim Jun 16 '17 at 07:12
this link is helpful for you https://medium.com/react-native-training/deep-linking-your-react-native-app-d87c39a1ad5e – Arunkumar Jun 16 '17 at 07:26
7

Thanks. I can do it with `Linking.openURL('app-settings://notification/myapp')}` – JuntaeKim Jun 20 '17 at 02:51
3

Is there any solution for android which does not require an external lib? – Pavan Nov 17 '17 at 11:08
4

@Arunkumar Do you know the equivalent for Android? – wcandillon Nov 27 '17 at 15:16
@wcandillon sry I don't know, I'll check and let you know – Arunkumar Nov 28 '17 at 07:14
Will It make the reject in App Store – deva11 Jun 07 '18 at 06:49
how to open external app after button click in my app – Avishkar Patil Nov 18 '19 at 12:28

B. Mohammad · Answer 2 · 2021-03-30T17:49:05.830

14

Since React Native 0.60 to open App settings use:


import { Linking } from 'react-native';

Linking.openSettings();

Open the Settings app and displays the app’s custom settings, if it has any.

Works for Android and iOS

edited Mar 30 '21 at 17:49

answered Sep 20 '19 at 10:48

B. Mohammad

1,320
6
24

1

is there way to open the Location permistion setting directly? – Oliver D Apr 23 '20 at 15:23
1

try this `Linking.openURL('App-Prefs:LOCATION_SERVICES')` – B. Mohammad Apr 23 '20 at 15:31
I got this error `Could not open URL 'App-Prefs:LOCATION_SERVICES': No Activity found to handle Intent { act=android.intent.action.VIEW dat=app-prefs:LOCATION_SERVICES flg=0x10000000 }` – Oliver D Apr 23 '20 at 16:15
1

Ah sorry this is for ios. For android i use this library 'react-native-settings' – B. Mohammad Apr 23 '20 at 16:48

score 5 · Answer 3 · answered Oct 02 '18 at 10:36

5

Use Linking.openURL. For example, below is how to check and open Health app on iOS

import { Linking } from 'react-native'

async goToSettings() {
  const healthAppUrl = 'x-apple-health://'
  const canOpenHealthApp = await Linking.canOpenURL(healthAppUrl)
  if (canOpenHealthApp) {
    Linking.openURL(healthAppUrl)
  } else {
    Linking.openURL('app-settings:')
  }
}

answered Oct 02 '18 at 10:36

onmyway133

38,911
23
231
237

how to open external app after button click in my app – Avishkar Patil Nov 18 '19 at 12:28

score 1 · Answer 4 · answered Jul 26 '17 at 16:22

1

To access specific settings screens, try this: Linking.openURL("App-Prefs:root=WIFI"); Linking to app-settings only opens the settings for the Reference: iOS Launching Settings -> Restrictions URL Scheme (note that prefs changed to App-Prefs in iOS 6)

answered Jul 26 '17 at 16:22

Julian K

1,453
2
17
19

has anyone else tried this? unfortunately it did not work for me on iOS 11 (both simulator and real device) – Antoni4 Mar 14 '18 at 16:18
Hey, thanks in my case 'App-Prefs:root' works for me – Nald Dev Jul 06 '20 at 13:10
1

as of iOS 14, what's working for me is Linking.openURL("App-prefs:General") - just remove `root=` from examples that have it – jes5199 Dec 02 '20 at 23:44

score 1 · Answer 5 · edited Jan 14 '21 at 05:49

1

Try this one for Open Specific System URL - Linking.openURL('App-Prefs:{3}')

edited Jan 14 '21 at 05:49

Yatin

2,348
6
20
38

answered May 11 '19 at 08:08

Karan Prajapati

57
3

score 0 · Answer 6 · answered Jan 06 '21 at 15:38

0

try this

Linking.openURL('app-settings://notification/myapp')

answered Jan 06 '21 at 15:38

Govan

940
1
10
11

score 0 · Answer 7 · answered May 26 '21 at 09:35

0

for iOS 14, this is how i open location service settings

Linking.openURL('App-Prefs:Privacy&path=LOCATION')

tested in react native 0.63.4

answered May 26 '21 at 09:35

Abid Khairy

371
3
7

React Native Open settings through Linking.openURL in IOS

7 Answers7

Linked