python: set one function to take the same arguments as another

Question

I have a class with a member that is a list of another class. So I want something like

class primary_class:
    def __init__(self):
        self.slist = []
    def add_secondary_class(self, <arguments>):
        self.slist.append(secondary_class(<arguments>))

Basically I want to be able to pass add_secondary_class arguments the exact same way I would pass them to the secondary_class constructor.

`*args` and `**kwargs` are way to go. https://stackoverflow.com/questions/3394835/args-and-kwargs — Łukasz Rogalski, Jun 12 '17 at 15:23
Have you actually tried it? Also, `*args` and `**kwargs` are very useful here — , Jun 12 '17 at 15:24

score 1 · Accepted Answer · answered Jun 12 '17 at 15:23

1

def add_secondary_class(self, *args):
    self.slist.append(secondary_class(*args))

or, if you have kwargs

def add_secondary_class(self, **kwargs):
    self.slist.append(secondary_class(**kwargs))

answered Jun 12 '17 at 15:23

codelessbugging

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Alas this doesn't do it. Using `**kwargs`, I end up with `TypeError: add_secondary_class() takes exactly 1 argument (8 given)` – goi42 Jun 12 '17 at 16:07
how did you call the function `add_secondary_class()`? – codelessbugging Jun 12 '17 at 16:10
`a = primary_class(); a.add_secondary_class()` – goi42 Jun 12 '17 at 16:11
with `kwargs` (keyword arguments) you need to call them as such `foo(bar=5, bar2='param2', bar3=[])`, i.e. with keywords – codelessbugging Jun 12 '17 at 16:12
Woops. Overlooked that I was adding some without keywords and some with. `def add_secondary_class(self,*args,**kwargs):` works perfectly. Thanks. – goi42 Jun 12 '17 at 16:16

python: set one function to take the same arguments as another

1 Answers1