how to hide soft keyboard in fragments?

Question

i want to hide keyboard in fragments in android.Because once it displays it remain visible in all fragments.I try this method

    public static void hideKeyboard(Context ctx) {
    InputMethodManager inputManager = (InputMethodManager) ctx
            .getSystemService(Context.INPUT_METHOD_SERVICE);

    // check if no view has focus:
    View v = ((Activity) ctx).getCurrentFocus();
    if (v == null)
        return;

    inputManager.hideSoftInputFromWindow(v.getWindowToken(), 0);
}

and call this method on button click

signIn.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
                hideKeyboard(ctx);
                login();


        }
    });

but this give error "java.lang.NullPointerException: Attempt to invoke virtual method 'java.lang.Object android.content.Context.getSystemService(java.lang.String)' on a null object reference"

why do you trying to find some view? pass View v as a parameter to your hideKeyboard method, v.getContext() will give you the right context and that would be method with 2 lines of code — Viktor Yakunin, May 28 '17 at 11:28
Have you initialized or assigned `ctx` with a Context object? — Wei Chan, May 28 '17 at 11:29
Possible duplicate of [Close/hide the Android Soft Keyboard](https://stackoverflow.com/questions/1109022/close-hide-the-android-soft-keyboard) — Viktor Yakunin, May 28 '17 at 11:45

Aniruddh Parihar · Accepted Answer · 2020-09-05T10:28:48.147

For Java

try this one

public static void hideSoftKeyboard(Activity activity) {
        if (activity.getCurrentFocus() == null) {
            return;
        }
        InputMethodManager inputMethodManager = (InputMethodManager) activity.getSystemService(Context.INPUT_METHOD_SERVICE);
        inputMethodManager.hideSoftInputFromWindow(activity.getCurrentFocus().getWindowToken(), 0);
    }

to call this just pass below code from your onclick of button

signIn.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
               hideSoftKeyboard(getActivity());
                login();


        }
    });

For Kotlin

fun hideSoftKeyboard(activity:Activity) {
  if (activity.getCurrentFocus() == null){
    return
  }
  val inputMethodManager = activity.getSystemService(Context.INPUT_METHOD_SERVICE) as InputMethodManager
  inputMethodManager.hideSoftInputFromWindow(activity.getCurrentFocus().getWindowToken(), 0)
}

pass below code from your onclick of button

signIn.setOnClickListener(object:View.OnClickListener() {
  fun onClick(v:View) {
    hideSoftKeyboard(getActivity())
    login()
  }
})

score 3 · Answer 2 · answered May 28 '17 at 11:39

signIn.setOnClickListener(new View.OnClickListener() {
   @Override
   public void onClick(View v) {
       hideKeyboard(v);
       login();
   }
});

And the hide keyboard method in some Utility class

public static void hideKeyboard(@NonNull View v) {
    InputMethodManager inputManager = (InputMethodManager) v.getContext()
            .getSystemService(Context.INPUT_METHOD_SERVICE);
    inputManager.hideSoftInputFromWindow(v.getWindowToken(), 0);
}

score 0 · Answer 3 · answered Jun 18 '20 at 06:35

Use this for kotlin users create a file and add this code

fun hideSoftKeyboard(activity: Activity) {
    if (activity.currentFocus == null) {
        return
    }
    val inputMethodManager =
        activity.getSystemService(Context.INPUT_METHOD_SERVICE) as InputMethodManager
    inputMethodManager.hideSoftInputFromWindow(activity.currentFocus!!.windowToken, 0)
}

Now call this method anywhere using

hideSoftKeyboard(requireActivity())

Happy coding..NB for kotlin

score -1 · Answer 4 · edited May 28 '17 at 12:30

-1

Try this:

View view = this.getCurrentFocus();
if (view != null) {
    InputMethodManager imm = (InputMethodManager)getSystemService(Context.INPUT_METHOD_SERVICE);
    imm.hideSoftInputFromWindow(view.getWindowToken(), 0);
}

edited May 28 '17 at 12:30

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answered May 28 '17 at 11:38

asmaa hassen

1

how to hide soft keyboard in fragments?

4 Answers4