Regular expression (regex) help: Need to delete everything on several lines after an IP address

Question

I have several lines that are

192.168.86.3 0x1 0x2 3cbbaxrad * br-lan 192.168.86.213 0x1 0x2 3cccfargarad * br-lan 192.168.86.51 0x1 0x2 3cccfcvrad * br-lan 192.168.86.11 0x1 0x2 3cccfxxrad * br-lan

I need to extract only the ip addresses so it's 192.168.86.3 192.168.86.213 192.168.86.51 192.168.86.11

Can anyone help? Thanks

Answer 1

This works for your test case:

\d*\.\d*\.\d*\.\d*

Answer 2

This is a good fit. It only picks up numeric sequences up to three digits and with periods in between. The ()'s make it a selection sequence. So that you can use a replacement string like $1 to only deposit IP addresses.

(\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3})

Try out this link for more help: https://regex101.com/r/p3NdGL/1