Android share link and images through my application

Question

I want to add the ability to share an image or link through my application. For this I added in the manifest those filters

<activity android:name="MyActivity" 
          android:launchMode="singleTask"
          android:screenOrientation="portrait"
>
    <intent-filter>
       <action android:name="android.intent.action.SEND" />
       <category android:name="android.intent.category.DEFAULT" />
       <data android:mimeType="image/*" />
    </intent-filter>
    <intent-filter>
       <action android:name="android.intent.action.SEND" />
       <category android:name="android.intent.category.DEFAULT" />
       <data android:mimeType="text/plain" />
   </intent-filter>
</activity>

this activity is basically the main one, I mean when the user will launch the application, this activity will be open.

now, when I swipe the application and share a youtube link through my application I get the data and it works fine, the problem is when I launch the application then press the home button (in this case the application is on background), and then try to share a youtube link I don't get the data from the intent.

any suggestions?

please post your data handling code too – mhdjazmati Feb 28 '17 at 13:02 — mhdjazmati, Feb 28 '17 at 13:02
Can you try without android:launchMode="singleTask"? – jakubbialkowski Feb 28 '17 at 13:07 — jakubbialkowski, Feb 28 '17 at 13:07

score 1 · Answer 1 · answered Feb 28 '17 at 13:02

1

it seems you are putting the data handling code inside your onCreate() .

try putting the data handling code inside your onStart() .

answered Feb 28 '17 at 13:02

mhdjazmati

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score 1 · Answer 2 · edited May 23 '17 at 12:00

1

When you share a link, the third-party application gives you data to share when it opens your application. But when you press the home button, data are not stored. Then, when you will back, data will be lost.

So, you need to store data when you retrieve data from the third-party application in a variable (for example).

Now, you can retrieve data with onStart() function and display on your view.

TIP: I guess you can use Singleton (also known as anti-pattern: read more).

edited May 23 '17 at 12:00

Community

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answered Feb 28 '17 at 13:03

Loic P.

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Don't you know that Singleton Pattern is as well the anti-pattern? – jakubbialkowski Feb 28 '17 at 13:05
it seems that you just rephrased my answer ! , instead of posting an answer try update mine ! . – mhdjazmati Feb 28 '17 at 13:07
You have posted your answer during my writing. – Loic P. Feb 28 '17 at 13:12
Yes @jakubbialkowski, according to [SO answer](http://stackoverflow.com/questions/137975/what-is-so-bad-about-singletons), I edited my answer. – Loic P. Feb 28 '17 at 13:15
well , that's okay then :D – mhdjazmati Feb 28 '17 at 13:17
@mhdjazmati :-D – Loic P. Feb 28 '17 at 13:18

score 1 · Accepted Answer · answered Feb 28 '17 at 13:10

1

Looks like you should add the handling not only in onCreate but as well in onNewIntent method. singleTask forces android to deliver the intent via onNewIntent if the activity is already created.

answered Feb 28 '17 at 13:10

jakubbialkowski

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Android share link and images through my application

3 Answers3