AVL tree, access pointer in struct

Question

#define LEFT   1
#define BAL    0
#define RIGHT -1

typedef struct avl {
    int value;
    int bal;
    struct avl *left, *right;
} *AVL;

AVL lower (AVL a){
    while ((a.left != NULL) || (a.right != NULL)) {
        if (a.bal = LEFT){
            AVL lower (a.left);
        } else AVL lower (a.right);
    }
    return (a);
}

In this code, I have a problem accessing the struct inside my struct. What should I write in this code where I have a.left, a.right? Thank you all.

The code won't run, it gets erros compiling, because I'm using something worng but I dont know how I should do it — Dost, Jan 25 '17 at 14:42
request for member ‘bal’ in something not a structure or union — Dost, Jan 25 '17 at 14:44

score 1 · Answer 1 · answered Jan 25 '17 at 14:45

1

a is an AVL, which is a pointer to a struct avl. Thus, to access a field of that structure, you'd need something like a->left.

answered Jan 25 '17 at 14:45

Scott Hunter

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AVL tree, access pointer in struct

1 Answers1