Looking for a string in Python

Question

I'm trying to use the regex module in Python. For example, I have two strings:

Профессиональная ГИС "Панорама" (версия 12.4.0, для платформы "x64")
Профессиональная ГИС "Панорама" (версия 12.4.0, для платформы "x32")

Numbers after 12 are changeable and can be more than two numbers. How can I catch, for example, all first strings?

@ScottHunter it was my fault not to demonstate efforts. But now it doesn't matter for me, duty to below answers i understood how do i have to work with regexp — user3798175, Jan 26 '17 at 12:18

Willem Van Onsem · Accepted Answer · 2017-01-24T12:44:42.427

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It is not entirely clear what the conditions are. Based on your comments I think you look for the following regex:

r"Профессиональная ГИС \"Панорама\" \(версия 12(\.\d+){2,}, для платформы \"x(32|64)\"\)"

This will match any sequence of dots and numbers after the 12. (so for instance 12.4.51.3.002 is allowed), and furthermore both x64 and x32 are allowed (not x42).

You can test the regex on regex101.

edited Jan 24 '17 at 12:44

answered Jan 24 '17 at 12:33

Willem Van Onsem

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Thank you very much, now i understood more. I have tried this service, but maybe have had some dullness – user3798175 Jan 24 '17 at 12:44

score 0 · Answer 2 · edited Sep 01 '17 at 00:10

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You can try the below one. If you have optional numbers after 12, you can include the ? symbol to match the regular expression.

 Профессиональная ГИС "Панорама" \(версия 12.[0-9]?[0-9].[0-9]?[0-9], для платформы "x(32|64)"\)

edited Sep 01 '17 at 00:10

Peter Mortensen

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answered Jan 24 '17 at 12:35

A user

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Looking for a string in Python

2 Answers2