many examples in SO are fixing both sides, the leading and trailing. My request is only about the trailing. My input text is: " keep my left side " Desired output: " keep my left side"
Of course this command will remove both ends:
let cleansed = messageText.trimmingCharacters(in: .whitespacesAndNewlines)
Which won't work for me.
How can I do it?
A quite simple solution is regular expression, the pattern is one or more(+) whitespace characters(\s) at the end of the string($)
let string = " keep my left side "
let cleansed = string.replacingOccurrences(of: "\\s+$",
with: "",
options: .regularExpression)
You can use the rangeOfCharacter function on string with a characterSet. This extension then uses recursion of there are multiple spaces to trim. This will be efficient if you only usually have a small number of spaces.
extension String {
func trailingTrim(_ characterSet : CharacterSet) -> String {
if let range = rangeOfCharacter(from: characterSet, options: [.anchored, .backwards]) {
return self.substring(to: range.lowerBound).trailingTrim(characterSet)
}
return self
}
}
"1234 ".trailingTrim(.whitespaces)
returns
"1234"
Building on vadian's answer I found for Swift 3 at the time of writing that I had to include a range parameter. So:
func trailingTrim(with string : String) -> String {
let start = string.startIndex
let end = string.endIndex
let range: Range<String.Index> = Range<String.Index>(start: start, end: end)
let cleansed:String = string.stringByReplacingOccurrencesOfString("\\s+$",
withString: "",
options: .RegularExpressionSearch,
range: range)
return cleansed
}
Simple. No regular expressions needed.
extension String {
func trimRight() -> String {
let c = reversed().drop(while: { $0.isWhitespace }).reversed()
return String(c)
}
}
