Regular expression is matching entire string

Question

I am trying to get the base64 part of the following (including the base64: portion) with this regular expression:

.+\[?(.+?)\]?

and with this example text:

Application key [base64:HlOiabVcCmzUvcnPuCHCOS6nvS89otzCBXKb/PVbI1g=] set successfully.

Or this text (this is also an example result):

base64:zI1EaQeidtfpLwE9b8sGo5sZDbnzAqULCnL2hT3HoJo=

When I run it though, it matches the entire string.

Possible duplicate of [RegEx to parse or validate Base64 data](http://stackoverflow.com/questions/475074/regex-to-parse-or-validate-base64-data) — Pedro Lobito, Dec 18 '16 at 02:39
@PedroLobito, note that it's indeed a base64, but the structure here is a bit different. — Dekel, Dec 18 '16 at 02:41
I am also not 100% sure it is always going to be a base64. This is a returned result of another program. — Get Off My Lawn, Dec 18 '16 at 02:42
I guess, but for now I will assume that the program always returns a base64, which should be good enough for my purposes. — Get Off My Lawn, Dec 18 '16 at 02:45

score 1 · Accepted Answer · answered Dec 18 '16 at 02:32

1

How about this one:

base64:([^\] \b]*)

Catch every char that is not ], and \b(=word boundry) after a base64:

answered Dec 18 '16 at 02:32

Dekel

1 Answers1