Syntax error Cygwin If Else condition

Question

I am using Cygwin to run a script, I am getting syntax error when i use if else condition. Can you please tell me what is wrong with my script ?

./test.sh: line 10: syntax error near unexpected token else' ./test.sh: line 10:else '

#!/bin/bash
date
schema=''
table='JJJJ'
first=${table:0:1}
echo $first
if [$first == 'J'] 
echo 'SUCCESS';
else 
echo 'error';
fi

thanks

You're missing a `then`. And a space between `[` and `$first`. May I suggest using http://www.shellcheck.net? — Biffen, Dec 07 '16 at 11:20

score 2 · Accepted Answer · answered Dec 07 '16 at 11:22

2

Your if statement is incorrect:

if [ "$first" == 'J' ]; then
  echo 'SUCCESS';
else 
  echo 'error';
fi

Note the then statement and the double quote for the $first variable.

answered Dec 07 '16 at 11:22

oliv

score 1 · Answer 2 · answered Dec 07 '16 at 11:21

1

Use shellcheck.net for stuff like this. You have syntax errors around your if.

Correct code-

#!/bin/bash
date
schema=''
table='JJJJ'
first=${table:0:1}
echo $first
if [ $first == 'J' ] 
then
echo 'SUCCESS';
else 
echo 'error';
fi

answered Dec 07 '16 at 11:21

Chem-man17

2 Answers2