multiple string replace using variable

Question

I have to replace multiple words in a string.

my code is like this

var csku = "{len}";
 var value = 5;
 var finalPrice = "({con}*{len})+{wid}+{fixed_var}+{extra}+{sqft}+{len}";
console.log(finalPrice.replace(csku, value));

Using this code I got this solution

({con}*5)+{wid}+{fixed_var}+{extra}+{sqft}+{len}

but I want this

({con}*5)+{wid}+{fixed_var}+{extra}+{sqft}+5

I google it for replacing multiple words in the string using one call I find this

str.replace(/X|x/g, '');

Here / and g is used for multiple replace and in this format I have to add static word but in my code csku is not fixed so how can I replace all words in one call using variable

There is no jQuery in your question. – mplungjan Oct 17 '16 at 08:03 — mplungjan, Oct 17 '16 at 08:03

mplungjan · Accepted Answer · 2016-10-17T08:23:36.967

1

Using the code from the duplicate to create a Regex object using the variable

var csku = "{len}";
var value = 5;
var finalPrice = "({con}*{len})+{wid}+{fixed_var}+{extra}+{sqft}+{len}";
var re = new RegExp(csku, "g");
console.log(finalPrice.replace(re, value));

edited Oct 17 '16 at 08:23

answered Oct 17 '16 at 08:07

mplungjan

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score 1 · Answer 2 · answered Oct 17 '16 at 08:10

use new RegExp(cksu, 'g') to create a regular expression that'll match all cksu.

new RegExp('{len}', 'g') will return /{len}/g meaning all global matches.

so finalPrice.replace(new RegExp(cksu, 'g'), value) will replace all global matches of cksu with value.

var csku = "{len}";
var value = 5;
var finalPrice = "({con}*{len})+{wid}+{fixed_var}+{extra}+{sqft}+{len}";

console.log(finalPrice.replace(new RegExp(csku, 'g'), value));

score -2 · Answer 3 · answered Oct 17 '16 at 08:04

Standart replace function change just first match. You can use this function:

function ReplaceAll(Source, stringToFind, stringToReplace) {
            var temp = Source;
            var index = temp.indexOf(stringToFind);
            while (index != -1) {
                temp = temp.replace(stringToFind, stringToReplace);
                index = temp.indexOf(stringToFind);
            }
            return temp;
        }

multiple string replace using variable

3 Answers3