0
"use strict";
function square(x) {
    return x * x;
}
function add(square,y) {
    return square(4) +y
    document.write(square + y)
}
add(4,1);
console.log(add(4,1));

I have to use a function as in the parameter of another function. I am trying to output 17.

Fengyang Wang
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2 Answers2

2

Just call it as such:

add(square,1);

you may also want to change 

function add(square,y) {
    return square(4) +y
    document.write(square + y)
}

to be:

function add(square,y) {
    document.write(square(4) + y)        
    return square(4) +y
}

Per Andrew's comment, it might also be a good choice to change document.write calls to be console.log and open the browser console to read results.

httpNick
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    Also add that `document.write` *is highly discouraged*. – Andrew Li Oct 06 '16 at 00:50
  • true, you can [read more here](http://stackoverflow.com/questions/802854/why-is-document-write-considered-a-bad-practice) about why @AndrewL.is saying that. – httpNick Oct 06 '16 at 00:51
  • Thank you so much Andrew I find this concept quite confusing could you recommend any tutorials that actually teach this –  Oct 06 '16 at 01:44
2

Probably easier to visualize if you change the argument name in your function declaration to be more generic but also more identifiable as a function requirement.

The name you use here is not relevant to the name of the function you will actually pass in

function add(func, num) {
    document.write(func(4) + num);
    return func(4) + num;    
}

add(square,1);

Then in another call you might do

add(myOtherCalcFunction, 6);
charlietfl
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