PHP shell_exec() SASS --update

Question

I am trying to execute sass --update via PHP shell_exec() function and get an error:

H:\SERVER\htdocs\path\to\project>sass --style compressed --update sass\:deployment\css\ 'sass' is not recognized as an internal or external command, operable program or batch file.

If I run the same command from the cmd manually - it works fine. The current folder is correct - checked with the getcwd()

Hayden Schiff · Accepted Answer · 2016-09-15T13:31:23.787

1

When you run the command sass in a shell, your computer has to find the executable program called sass somewhere on your computer. To do this, it looks through a series of folders called your PATH. Your PHP server is most likely running with a different PATH than your command prompt, and as such, is not able to find the executable.

To fix this: From your command prompt, where sass DOES work, run this command: which sass (on Windows, instead use where sass)

That will tell you the exact location of sass (for example, it might be /usr/bin/sass or something like that). Once you have that value, replace "sass" in your PHP code with that entire location.

edited Sep 15 '16 at 13:31

answered Sep 14 '16 at 02:51

Hayden Schiff

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Err, is the command just 'which sass'? "'which' is not recognized as an internal or external command, operable program or batch file." – Anastasia Sitnina Sep 14 '16 at 11:38
Oh huh, I guess on Windows you have to use "where" instead. https://stackoverflow.com/questions/304319/is-there-an-equivalent-of-which-on-the-windows-command-line – Hayden Schiff Sep 14 '16 at 13:23
Yes, that's it! It gave me the Path :) – Anastasia Sitnina Sep 14 '16 at 19:12

PHP shell_exec() SASS --update

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