Sublime Regex extract

Question

<.*>|\n.*\s.*\sid="(\w*)".*\n+|.*>\n|\n.+

and replace $1

This regex can take all id out from file

<a href="java" class="total" id="maker" placeholder="getTheResult('local6')">master6<a>

Result is maker

How can I extract getTheResult key name?

so my result will be local6

Tried   <.*>|\n.*\s.*\sgetTheResult('(\w*)').*\n+|.*>\n|\n.+ but didn't helped

No idea why you need that strange regex, but if you want to match a `(` or `)`, you need to escape them. `getTheResult$'(\w*$')` — Wiktor Stribiżew, Aug 08 '16 at 10:57
I meant `getTheResult$'(\w*)'$` (the literal parentheses are those outside `''`). Could you provide a bit more of the input file? I doubt you need that much of a pattern here. — Wiktor Stribiżew, Aug 08 '16 at 11:03
I'd use this `getTheResult$'([^']*)'$|(?:(?!getTheResult\(')[\s\S])*` and replace with `$1\n`. Please check. — Wiktor Stribiżew, Aug 08 '16 at 11:33
yes it did worked do you know how can i added space or , between extracted words , Thanks If i use $1, it adds , multiple times — Kunal Vashist, Aug 08 '16 at 11:37

score 1 · Accepted Answer · edited May 23 '17 at 11:51

I assume that:

you have files with text like getTheResult('local6')
you may have several values like that on a line
you'd like to keep those text only, one value per line.

I suggest

getTheResult\('([^']*)'\)|(?:(?!getTheResult\(')[\s\S])*

and replace with $1\n. The \n will insert a newline between the values. You can then use ^\n regex (to replace with empty string) to remove empty lines.

Pattern details:

getTheResult\(' - matches getTheResult(' as a literal string (note the ( is escaped)
([^']*) - Group 1 capturing 0+ chars other than '
'\) - a literal ')
| - or
(?:(?!getTheResult\(')[\s\S])* - 0+ chars that are not starting chars of the getTheResult(' character sequence (this is a tempered greedy token).

Sublime Regex extract

1 Answers1