PHP day / time logic

Question

I am looking to create a bespoke bit of PHP to work out based on the time of day whether a shop is open or closed.

The shop opening times are: Mon-Sat: 0700-1300, 1400-1800 (e.g. closed between 13:00 and 14:00), Sun: 0700-1230

So, I need the code to work out:

If its Mon,Tues,Wed,Thur,Fri or Sat and between 07:00 and 13:00, or between 14:00 and 18:00, or if its Sun between 07:00 and 12:30 echo

OPEN

else echo CLOSED.

Cant seem to get it to work... What I have is a bunch of IF statements in isolation from each other which works - but I need it to work in one IF statement..

What I have is below:

<!-- Is it a sunday? -->
<?php if (date('l') >= Monday || Tuesday || Wednesday || Thursday || Friday || Saturday) : ?>
<p>It's not Sunday</p>
<?php $dayType = 1; ?>
<?php else : ?>
<p>It is Sunday</p>
<?php $dayType = 2; ?>
<?php endif; ?>

<!-- is it between 8 and 18? -->
<?php if ($dayType = 1 && current_time('H') >= 8 && current_time('H') < 18) : ?>
<p>Not Sunday and Open</p>
<?php $dayTypeStatus = 11; ?>
<?php else : ?>
<p>Not Sunday and Closed</p>
<?php $dayTypeStatus = 10; ?>
<?php endif; ?>

<!-- Is it between 13 and 14? -->
<?php if ($dayType = 1 && $dayTypeStatus = 11 && current_time('H') >= 13 && current_time('H') < 14) : ?>
<p>Not Sunday and Open - Lunchtime</p>
<?php $dayTypeStatusLunch = 111; ?>
<?php else : ?>
<p>Not Sunday and Open - Not Lunchtime</p>
<?php $dayTypeStatusLunch = 110; ?>
<?php endif; ?>

<!-- Is it between 8 and 12:30 on a sunday? -->
<?php if (date('l') >= Sunday && current_time('H') >= 8 && current_time('H:i') < "12:30") : ?>
<p>Sunday Open</p>
<?php else : ?>
<p>Sunday Closed</p>
<?php endif; ?>

Any ideas to make it work?

Better attempt at code is as below:

<?php if (date('l') != Sunday && current_time('H') >= 7 && current_time('H') < 18) : ?>
<p>OPEN</p>
<?php else : ?>
<p>CLOSED</p>
<?php endif; ?>

But still missing the lunchtime close element and also including the sunday opening hours check - e.g. this works to check if its not a sunday and is between 0700 and 1800.

UPDATE - think this works???

<?php if (date('l') != "Sunday" && current_time('H') >= 7 && current_time('H') < 13 || current_time('H') >= 14 && current_time('H') < 18 || date('l') == "Sunday" && current_time('H') >= 8 && current_time('H:i') < "12:30") : ?>
<p>OPEN</p>
<?php else : ?>
<p>CLOSED</p>
<?php endif; ?>

`date('l') >= Monday || Tuesday ...` is absolute nonsense. This is actually supposed to work?! — deceze, Jul 14 '16 at 15:10
See update for the more recent version I have which is getting closer — dubbs, Jul 14 '16 at 15:12
`date('l') != Sunday` unless you've defined `Sunday` as a constant the PHP interpreter should be throwing a wobbly... — CD001, Jul 14 '16 at 15:13
OK... as you can tell I am a PHP novice.. so welcome your assistance and skills here chaps as I clearly need some heavy guidance! ;) — dubbs, Jul 14 '16 at 15:16
@dubbs at the place of `Sunday` it should be `"Sunday"` , as the `Sunday` is not defined as constant , so you have to make it a string by putting it inside quotes. — Arsh Singh, Jul 14 '16 at 15:19
I'd recommend taking a look at the `DateTime` class (http://php.net/manual/en/class.datetime.php) in PHP that should get you a decent idea of what's possible... and remember strings need to be quoted one way or another (http://php.net/manual/en/language.types.string.php) ... and you probably want to switch on error trapping (http://stackoverflow.com/questions/1053424/how-do-i-get-php-errors-to-display), PHP does give generally reasonably useful pointers about what's going wrong and where. — CD001, Jul 14 '16 at 15:20
Thanks - think I have just got it working - see latest edit to the question above... Let me know? — dubbs, Jul 14 '16 at 15:40

score 0 · Accepted Answer · answered Jul 14 '16 at 15:31

0

What about this?

<?php
///
if(date('w') !== 0) { //not sunday
  if((date('H')<18 && date('H')>=14) || (date('H')<13 && date('H')>=7)) {
    echo 'OPEN';
  }
  else {
    echo 'CLOSED';
  }
}
else if(intval(date('Hi'))<1230 && date('H')>=7) {
  echo 'OPEN';
}
else {
  echo 'CLOSED';
}

answered Jul 14 '16 at 15:31

Konstantinos Tsourdinis

135
5

Thanks - Does the version as the last edit in my question work / do the same thing? – dubbs Jul 14 '16 at 15:41
Thanks - Could you explain what the issue is with how I have it? I'd like to learn why its wrong // thanks – dubbs Jul 14 '16 at 15:49
The && and || are dangerusly mixed, if you wish to improve it go step by step using parenthesis adding a statement per time and test. – Konstantinos Tsourdinis Jul 14 '16 at 15:54
Konstantinos - This doesn't seem to work on reflection... I think the issue is related to the equal to or less than time bits - e.g. its now 14:15 on a Thursday - so the code so say shop is open - yet it says its closed... – dubbs Jul 15 '16 at 13:15
Are you sure you refresh browser? Because it works fine to me. – Konstantinos Tsourdinis Jul 15 '16 at 14:46
OK I think you do not have set your timezone. Add at the top of your script date_default_timezone_set('America/Los_Angeles'); or your own timezone. – Konstantinos Tsourdinis Jul 15 '16 at 15:06
Yeh, figured it was a timezones thing - so in the end used current_time rather than date - works that way – dubbs Jul 15 '16 at 15:43
Nice! Have in mind that current_time() is a wordpress function! – Konstantinos Tsourdinis Jul 15 '16 at 16:01

xottabych007 · Answer 2 · 2016-07-14T15:46:22.070

0

You could form a binary flag, based on the conditions and watch the current state by output code.

<?php
        // not sunday
$lol = (date('N')<7) << 0 | 
(current_time('H') >= 8 && current_time('H') < 18) << 1 | 
(current_time('H') >= 13 && current_time('H') < 14) << 2 |
(current_time('H') >= 8 && current_time('H:i') < "12:30") << 3;

That will give you an unique code for each situation

fiddle

edited Jul 14 '16 at 15:46

answered Jul 14 '16 at 15:39

xottabych007

142
2
10

PHP day / time logic

2 Answers2