How to return position of last char occurance?

Question

I'm using WDL_String container to manage string within a C++ Framework. I need to split a string (delimiter \) and get the last occurrence.

I can use the native method:

mFilePath.DeleteSub(mLastOccPosition, mFilePath.GetLength());

subbing the string, but I don't know how to catch the mLastOccPosition.

So if I have this string:

D:\\Google Drive\\My Files\\Test.zip

I need to return Test.zip. What's the best way to do this in C++?

see this http://stackoverflow.com/questions/14265581/parse-split-a-string-in-c-using-string-delimiter-standard-c — F.bernal, Jun 10 '16 at 08:47
If I am not mistaken, according to the code you linked, doesn't `mFilePath.get_filepart()` give you what you want? — Galik, Jun 10 '16 at 10:35

score 1 · Accepted Answer · answered Jun 10 '16 at 08:48

1

If s is an instance of std::string, then s.find_last_of('\\') would do it.

It returns std::string::npos if it can't be found.

You can then use std::string::substr to extract the bit you need.

answered Jun 10 '16 at 08:48

Bathsheba

As I said, I'm not working with string. But WDL_String. I can get `char*` from WDL_String. – markzzz Jun 10 '16 at 08:49
Well, you did ask for the best way, and that's probably to write `std::string s(/*the function that gets the char* */)`, and go from there. There's no point in building the extraction code from scratch. – Bathsheba Jun 10 '16 at 08:50
Is it nice somethings like this? (I don't need any reference to string): `(string(mFilePath.Get())).find_last_of('\\')` – markzzz Jun 10 '16 at 09:08
That would do it. (Although you might want to keep the string around if you want to use it for the extraction of the file name). Note that `std::string::npos` is a *constant* and does not require a string instance. – Bathsheba Jun 10 '16 at 09:10

1 Answers1