Javascript Regex Resources

Question

Im trying to decode this regex statement in javascript, im new to regex and cant find many good resources.

I think the below means find any characters between two single quotes is that correct and what does each character mean in this statement?

From what i understand so far is the first / and last / tell js to look for a pattern.

Can anyone break this regex down into pieces?

    mystring = mystring.match(/'([^']+)'/)[0];

https://developer.mozilla.org/en/docs/Web/JavaScript/Guide/Regular_Expressions http://www.regular-expressions.info/ http://regex101.com/ — zerkms, May 27 '16 at 01:14
Look at the return type for [`.match()`](https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/match). It returns an array or null. — 4castle, May 27 '16 at 01:16
Give a look at the top-right panel in this site: _https://regex101.com/r/vC6eW1/1_ — Washington Guedes, May 27 '16 at 01:18
I wrote the following book, free and it might be of help. https://www.syncfusion.com/resources/techportal/details/ebooks/regularexpressions — Sparky, May 27 '16 at 01:48

Vignesh Chinnaiyan · Accepted Answer · 2016-05-27T01:37:39.223

Yes you are right, this finds the word or a character that is in between the single quotes. you can view the below code for example.

var mystring ="This is 'some' random 'test' with string";
mystring = mystring.match(/'([^']+)'/)[0];
alert(mystring); // This alerts 'some'

Explanation:

/'([^']+)'/

' matches the character ' literally

1st Capturing group ([^']+)

[^']+ match a single character not present in the list below

Quantifier: + Between one and unlimited times, as many times as possible, giving back as needed [greedy]

' the literal character '

' matches the character ' literally

1 Answers1