Change background color on mouseover and remove it after mouseout

Question

I have table which class is forum. My jquery code:

<script type="text/javascript">
    $(document).ready(function() {
        $('.forum').bind("mouseover", function(){
            var color  = $(this).css("background-color");

            $(this).css("background", "#380606");

            $(this).bind("mouseout", function(){
                $(this).css("background", color);
            })    
        })    
    })
</script>

It perfectly works, but is it possible to do it in more efficient way without var color = $(this).css("background-color");. Just after mouseout leave the previous background-color and remove #380606? Thank you.

Is there a reason you need it in JQuery out of interest? As this is the type of thing CSS is used for, so one of the answers below would be ideal in most situations. — Amadiere, Sep 18 '10 at 10:03

kennytm · Accepted Answer · 2016-06-25T18:03:16.630

If you don't care about IE ≤6, you could use pure CSS ...

.forum:hover { background-color: #380606; }

.forum { color: white; }
.forum:hover { background-color: #380606 !important; }
/* we use !important here to override specificity. see http://stackoverflow.com/q/5805040/ */

#blue { background-color: blue; }

<meta charset=utf-8>

<p class="forum" style="background-color:red;">Red</p>
<p class="forum" style="background:green;">Green</p>
<p class="forum" id="blue">Blue</p>

With jQuery, usually it is better to create a specific class for this style:

.forum_hover { background-color: #380606; }

and then apply the class on mouseover, and remove it on mouseout.

$('.forum').hover(function(){$(this).toggleClass('forum_hover');});

$(document).ready(function(){
  $('.forum').hover(function(){$(this).toggleClass('forum_hover');});
});

.forum_hover { background-color: #380606 !important; }

.forum { color: white; }
#blue { background-color: blue; }

<meta charset=utf-8>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<p class="forum" style="background-color:red;">Red</p>
<p class="forum" style="background:green;">Green</p>
<p class="forum" id="blue">Blue</p>

If you must not modify the class, you could save the original background color in .data():

  $('.forum').data('bgcolor', '#380606').hover(function(){
    var $this = $(this);
    var newBgc = $this.data('bgcolor');
    $this.data('bgcolor', $this.css('background-color')).css('background-color', newBgc);
  });

$(document).ready(function(){
  $('.forum').data('bgcolor', '#380606').hover(function(){
    var $this = $(this);
    var newBgc = $this.data('bgcolor');
    $this.data('bgcolor', $this.css('background-color')).css('background-color', newBgc);
  });
});

.forum { color: white; }
#blue { background-color: blue; }

<meta charset=utf-8>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<p class="forum" style="background-color:red;">Red</p>
<p class="forum" style="background:green;">Green</p>
<p class="forum" id="blue">Blue</p>

or

  $('.forum').hover(
    function(){
      var $this = $(this);
      $this.data('bgcolor', $this.css('background-color')).css('background-color', '#380606');
    },
    function(){
      var $this = $(this);
      $this.css('background-color', $this.data('bgcolor'));
    }
  );

$(document).ready(function(){
  $('.forum').hover(
    function(){
      var $this = $(this);
      $this.data('bgcolor', $this.css('background-color')).css('background-color', '#380606');
    },
    function(){
      var $this = $(this);
      $this.css('background-color', $this.data('bgcolor'));
    }
  );    
});

.forum { color: white; }
#blue { background-color: blue; }

<meta charset=utf-8>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<p class="forum" style="background-color:red;">Red</p>
<p class="forum" style="background:green;">Green</p>
<p class="forum" id="blue">Blue</p>

No, I need this done in Jquery actually, it is just a one piece of code. — good_evening, Sep 18 '10 at 09:56

Marc Uberstein · Answer 2 · 2012-05-08T08:31:14.900

20

Set the original background-color in you CSS file:

.forum{
    background-color:#f0f;
}

You don't have to capture the original color in jQuery. Remember that jQuery will alter the style INLINE, so by setting the background-color to null you will get the same result.

$(function() {
    $(".forum").hover(
    function() {
        $(this).css('background-color', '#ff0')
    }, function() {
        $(this).css('background-color', '')
    });
});

edited May 08 '12 at 08:31

answered Sep 18 '10 at 12:47

Marc Uberstein

12,143
3
41
68

1

That is a great answer! and it works perfectly... Tested in firebugs – Joberror Sep 19 '10 at 01:34
Thanks, appreciated! If you want, you can include the jquery.color plugin. Then you have the ability to change color with animation. e.g. $(this).animate({backgroundColor:'#ff0'},400); – Marc Uberstein Sep 19 '10 at 07:10

Pramendra Gupta · Answer 3 · 2010-09-19T02:01:09.823

Try this , its working and simple

HTML

<html>
<head></head>
<body>
    <div class="forum">
        test
    </div>
</body>
</html>

Javascript

$(document).ready(function() {
    var colorOrig=$(".forum").css('background-color');
    $(".forum").hover(
    function() {
        //mouse over
        $(this).css('background', '#ff0')
    }, function() {
        //mouse out
        $(this).css('background', colorOrig)
    });
});

css

.forum{
    background:#f0f;
}

live demo

http://jsfiddle.net/caBzg/

your variable colorOrig will return null as the css property "background" selector is unreadable by jQuery... use "background-color" or "backgroundColor" instead — Joberror, Sep 19 '10 at 01:22

score 3 · Answer 4 · answered Sep 18 '10 at 09:55

This should be set directly in the CSS.

.forum {background-color: #123456}
.forum:hover {background-color: #380606}

If you are worried about the fact the IE6 will not accept hover over elements which are not links, you can use the hover event of jQuery for compatibility.

score 1 · Answer 5 · edited Nov 23 '12 at 13:42

1

HTML:

<div id="id">
</div>
<div id="hiddenDiv" style="display:none;"></div>

jQuery:

$('#id').hover(function(){
    $("#hiddenDiv").css('display','block');
  },
  function(){
    $("#hiddenDiv").css('display','none');
  }
);

edited Nov 23 '12 at 13:42

bluish

23,093
23
110
171

answered Apr 29 '11 at 04:48

anuja

11
1

Abhishek Goel · Answer 6 · 2013-06-08T07:55:25.667

After lot of struggle finally got it working. ( Perfectly tested)

The below example will also support the fact that color of already clicked button should not be changes

JQuery Code

var flag = 0; // Flag is to check if you are hovering on already clicked item

$("a").click(function() {
    $('a').removeClass("YourColorClass");
    $(this).addClass("YourColorClass");
    flag=1;
}); 

$("a").mouseover(function() {
    if ($(this).hasClass("YourColorClass")) {
        flag=1;
    }
    else{
        $(this).addClass("YourColorClass");
    };
});

$("a").mouseout(function() {
    if (flag == 0) {
        $(this).removeClass("YourColorClass");
    }
    else{
        flag = 0;
    }
});

score 0 · Answer 7 · answered Dec 06 '16 at 09:42

This is my solution :

$(document).ready(function () {
  $( "td" ).on({
    "click": clicked,
    "mouseover": hovered,
    "mouseout": mouseout
});

var flag=0;

function hovered(){
  $(this).css("background", "#380606");
}

function mouseout(){
  if (flag == 0){
  $(this).css("background", "#ffffff");
} else {
  flag=0;
}
}

function clicked(){
  $(this).css("background","#000000");
  flag=1;
}
})

Change background color on mouseover and remove it after mouseout

7 Answers7

Linked

Related