PHP sprintf escaping %

Question

I want the following output:-

About to deduct 50% of € 27.59 from your Top-Up account.

when I do something like this:-

$variablesArray[0] = '€';
$variablesArray[1] = 27.59;
$stringWithVariables = 'About to deduct 50% of %s %s from your Top-Up account.';
echo vsprintf($stringWithVariables, $variablesArray);

But it gives me this error vsprintf() [function.vsprintf]: Too few arguments in ... because it considers the % in 50% also for replacement. How do I escape it?

@Col. Shrapnel My question is about vsprintf not printf, I am using this for the first time and could not assume the similarity between the two. However, searching `escape` or `escaping` in both `php.net/printf` and `php.net/vsprintf` both does not show the answer immediately. When I search for `%%` it shows the answer in php.net/printf but I didn't know about `%%`!!! Did you search for the answer there before downvoting? — Sandeepan Nath, Sep 08 '10 at 10:40
@sandeepan: `vsprintf` belongs in the same family of functions as `printf`. The correct documentation to find the format, though, is http://www.php.net/sprintf. Both pages even point to it: "See sprintf() for a description of format." Didn't you at least click it? — BoltClock, Sep 08 '10 at 10:43
@Col. Shrapnel ok fine let's take php.net/sprintf, where is the answer? It is halfway down the page `With printf() and sprintf() functions, escape character is not backslash '\' but rather '%'.` What is there to downvote here? It was just not that obvious to me as it was to you. If you find a duplicate question you can better write the link. But I am sure many will find this question helpful. But you won't accept that and you will still say something, I know. — Sandeepan Nath, Sep 08 '10 at 10:49
oh I thought the second comment was by Col. Shrapnel , sorry — Sandeepan Nath, Sep 08 '10 at 10:51
SO should have a flag for RTFM responses. It's almost like people troll just so they can tell people to read the docs. He needed help and asked a question and then someone answered helpfully and got points for it. The world went on and the internet was used to someone's benefit. Meanwhile I'm getting heated over a two year old argument. — rob5408, Jul 02 '13 at 03:22

score 374 · Accepted Answer · answered Sep 08 '10 at 10:26

374

Escape it with another %:

$stringWithVariables = 'About to deduct 50%% of %s %s from your Top-Up account.';

answered Sep 08 '10 at 10:26

BoltClock

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23

sprintf("SELECT * FROM ... WHERE name LIKE '%%%s%%%s%%'", $fname, $lname); -- Ugly but it works! – Jan Hettich Oct 08 '11 at 22:57
you can add that part with another "%s": sprintf('from %s you can get %s', 'something', '50%') – Lukas Liesis May 12 '15 at 02:35
How do you escape it if the string is dynamic? Let's say, `sprintf('This is %s.', the_title())` – budji Nov 17 '15 at 10:10
7

@madastro `str_replace('%', '%%', the_title())` – Ivanka Todorova Jan 16 '17 at 13:11

score 5 · Answer 2 · answered Jul 02 '17 at 23:40

5

It is very easy.

Put another % in front of the original % to escape it.

For example,

$num=23;
printf("%%d of 23 = %d",$num);

Output:

%d of 23 = 23

answered Jul 02 '17 at 23:40

MohamadReza MohamadPouran · Answer 3 · 2021-05-24T14:27:12.493

1

For add % in your language string, you just need to add double percent %% instead of one

edited May 24 '21 at 14:27

answered May 24 '21 at 14:21

MohamadReza MohamadPouran

23
5

score 0 · Answer 4 · answered Oct 01 '17 at 14:48

0

What about this:

$variablesArray[0] = '%';
$variablesArray[1] = '€';
$variablesArray[2] = 27.59;
$stringWithVariables = 'About to deduct 50%s of %s %s from your Top-Up account.';
echo vsprintf($stringWithVariables, $variablesArray);

Just add your percent sign in your variables array

answered Oct 01 '17 at 14:48

3eighty

179
2
5

The question was how to sprintf escaping %. – Fatalist Oct 30 '20 at 18:23

score 0 · Answer 5 · answered Dec 08 '20 at 14:27

0

This works for me:

sprintf(
    '%s (Cash Discount: %%%s, Deferred Discount: %%%s)',
    $segment->name,
    $segment->discount_cash,
    $segment->discount_deferred,
)

// Gold (Cash Discount: %25, Deferred Discount: %20)

answered Dec 08 '20 at 14:27

Sinan Eldem

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2
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PHP sprintf escaping %

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