Java if string in variable

Question

very new to java, but I can't seem to find how to do this in java..

var1 = "testing101"
if("101" in testing) balala

How do I do in, in java?

import org.openqa.selenium.By;
import org.openqa.selenium.WebDriver;
import org.openqa.selenium.WebElement;
import org.openqa.selenium.chrome.ChromeDriver;




public class Main {
    public static void buttonPressed(String[] args) {

        WebDriver driver = new ChromeDriver();
        driver.get("http://www.csgodouble.com/index.php");
        WebElement rollingTimer = driver.findElement(By.xpath("//*[@id=\"banner\"]"));
        if(rollingTimer :: "Rolling in 41")

    }
}

this is how I thought it was done..

Possible duplicate of [In Java, how do I check if a string contains a substring (ignoring case)?](http://stackoverflow.com/questions/2275004/in-java-how-do-i-check-if-a-string-contains-a-substring-ignoring-case) — maximede, Mar 23 '16 at 22:45

Sam Orozco · Accepted Answer · 2016-03-23T22:52:58.040

4

If you trying to see if a string contains a sub string:

String var1 = "testing101"
if(var1.contains("101"))

edited Mar 23 '16 at 22:52

answered Mar 23 '16 at 22:43

Sam Orozco

1,120
11
22

Hmmm, is there something I need to import? says cannot resolve "contains" – Mar 23 '16 at 22:45
@user6069863 What type did you declare `var1` as? – azurefrog Mar 23 '16 at 22:47
Nevermind got it, f(rollingTimer.getText().contains("")); – Mar 23 '16 at 22:49

score 0 · Answer 2 · answered Mar 23 '16 at 22:44

0

I think you may want to use the contains method of String class.

answered Mar 23 '16 at 22:44

Cajova_Houba

44
1
9

score 0 · Answer 3 · answered Mar 23 '16 at 22:48

0

For a String in Java to see if a String is contained in another one do:

String str1 = "testing 1";
if(str1.contains("testing"))
{
     //Add your code here
 }

answered Mar 23 '16 at 22:48

mantlabs

352
2
6

score 0 · Answer 4 · answered Mar 23 '16 at 22:49

Likewise, you can compare string for equallity check,

    if("Rolling in 41".equals(rollingTimer )){ // compare with case-sensitive

    }

    // OR this way also

if("Rolling in 41".equalsIgnoreCase(rollingTimer )){ // compare without case-sensitive

    }

Java if string in variable

4 Answers4